We have: F = m×a
Here, m = 90 Kg
a = 15 m/s²
Substitute their values into the expression:
F = 90 × 15
F = 1350 N
In short, Your Answer would be Option D
Hope this helps!
Force = (mass) x (acceleration)
Force = (18 kg) x (3 m/s²) = 54 newtons
As long as you continue pushing the cart with 54 newtons of force,
it will accelerate at 3 m/s².
At the instant you release it, or keep your hands on it but stop pushing,
it will stop accelerating. It'll continue forward at the speed it had when
the 54 newtons of force stopped.
The doppler effect is the increase or decrease in the frequency of sound, light, or other waves as the source and observer move toward or away from each other.
Answer:
The loop penetrate 4 cm into the magnetic field.
Explanation:
Given that,
Width w= 5 cm
Length L= 10 cm
mass m = 40 g
Resistance R = 20 mΩ
Initial velocity = 1 m/s
Magnetic field = 2 T
We need to calculate the induced emf
Using formula of emf
![\epsilon=v_{0}Bw](https://tex.z-dn.net/?f=%5Cepsilon%3Dv_%7B0%7DBw)
Put the value into the formula
![\epsilon =1\times2\times5\times10^{-2}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D1%5Ctimes2%5Ctimes5%5Ctimes10%5E%7B-2%7D)
![\epsilon =10\times10^{-2}\ volt](https://tex.z-dn.net/?f=%5Cepsilon%20%3D10%5Ctimes10%5E%7B-2%7D%5C%20volt)
We need to calculate the current
Using Lenz's formula
![i=\dfrac{\epsilon}{R}](https://tex.z-dn.net/?f=i%3D%5Cdfrac%7B%5Cepsilon%7D%7BR%7D)
![i=\dfrac{10\times10^{-2}}{20\times10^{-3}}](https://tex.z-dn.net/?f=i%3D%5Cdfrac%7B10%5Ctimes10%5E%7B-2%7D%7D%7B20%5Ctimes10%5E%7B-3%7D%7D)
![i=5\ A](https://tex.z-dn.net/?f=i%3D5%5C%20A)
We need to calculate the force
Using formula of force
![F=i(\vec{w}\times\vec{B})](https://tex.z-dn.net/?f=F%3Di%28%5Cvec%7Bw%7D%5Ctimes%5Cvec%7BB%7D%29)
![F=iwB](https://tex.z-dn.net/?f=F%3DiwB)
Put the value into the formula
![F=5\times5\times10^{-2}\times2](https://tex.z-dn.net/?f=F%3D5%5Ctimes5%5Ctimes10%5E%7B-2%7D%5Ctimes2)
![F=0.5\ N](https://tex.z-dn.net/?f=F%3D0.5%5C%20N)
We need to calculate the acceleration
Using formula of acceleration
![a=\dfrac{F}{m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BF%7D%7Bm%7D)
Put the value in to the formula
![a=\dfrac{0.5}{40\times10^{-3}}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B0.5%7D%7B40%5Ctimes10%5E%7B-3%7D%7D)
![a=12.5\ m/s^2](https://tex.z-dn.net/?f=a%3D12.5%5C%20m%2Fs%5E2)
We need to calculate the distance
Using equation of motion
![v^2=u^2+2as](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2as)
![s=\dfrac{v^2-u^2}{2a}](https://tex.z-dn.net/?f=s%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2a%7D)
![s=\dfrac{0-1^2}{2\times(-12.5)}](https://tex.z-dn.net/?f=s%3D%5Cdfrac%7B0-1%5E2%7D%7B2%5Ctimes%28-12.5%29%7D)
![s=0.04\ m](https://tex.z-dn.net/?f=s%3D0.04%5C%20m)
![s=4\ cm](https://tex.z-dn.net/?f=s%3D4%5C%20cm)
Hence, The loop penetrate 4 cm into the magnetic field.