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never [62]
4 years ago
7

1. If x-1 is a factor of p(x)=x^3-7x^2+15x-9, which of the following represents the complete factorization for p(x)?

Mathematics
2 answers:
Marina CMI [18]4 years ago
7 0

Answer:

1. Option B is the correct answer.

2. The point (1,0) lies on the graph of p(x)=x⁴-2x³-x+2.

Step-by-step explanation:

1. Dividing x³-7x²+15x-9 with (x-1).

      \frac{x^3-7x^2+15x-9}{x-1}=x^2-6x+9

  Factorizing x²-6x+9 we will get

       x²-6x+9 = (x - 3)(x-3)

  x³-7x²+15x-9 = (x-1)(x - 3)(x-3)

  Option B is the correct answer.

2. We have p(x)=x⁴-2x³-x+2

   That is y = x⁴-2x³-x+2

   We have coordinates (1,0), substituting

   y = 1⁴-2 x 1³-1+2 = 0

   So when we are substituting x value as 1 we are getting y as zero, so the point lies in curve.

Snezhnost [94]4 years ago
4 0
<span>1.</span>divide P(x) by (x-1) to get the quadratic equation... from which can be solve using any method in finding the roots of quadratic equation.... 
2 true

branlist pls
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4 years ago
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Answer:

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Step-by-step explanation:

7 0
4 years ago
25 divided 5 + 7 - [ 4 x 3 ] =
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3 years ago
System of Equations <br> Need help<br> Trig
Yanka [14]

Looks like the system is

\begin{cases}-2x+y+6z=1\\3x+2y+5z=16\\7x+3y-4z=11\end{cases}

We can eliminate y by taking

(3x+2y+5z)-2(-2x+y+6z)=16-2(1)

\implies3x+2y+5z+4x-2y-12z=16-2

\implies7x-7z=14

\implies x-z=2

so that z=x-2, and

(7x+3y-4z)-3(-2x+y+6z)=11-3(1)

\implies7x+3y-4z+6x-3y-18z=11-3

\implies13x-22z=8

Substitute z=x-2 into this last equation and solve for x:

13x-22(x-2)=8

\implies13x-22x+44=8

\implies-9x=-36

\implies x=4

Then

z=x-2

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\implies z=2

Plug these values into any one of the original equation to solve for y:

-2x+y+6z=1

\implies-2(4)+y+6(2)=1

\implies-8+y+12=1

\implies y=-3

Hence the solution is x = 4, y = -3, and z = 2.

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4 years ago
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Lilit [14]

Answer:

n=5

Step-by-step explanation:

7 0
3 years ago
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