Answer:
1. Option B is the correct answer.
2. The point (1,0) lies on the graph of p(x)=x⁴-2x³-x+2.
Step-by-step explanation:
1. Dividing x³-7x²+15x-9 with (x-1).
Factorizing x²-6x+9 we will get
x²-6x+9 = (x - 3)(x-3)
x³-7x²+15x-9 = (x-1)(x - 3)(x-3)
Option B is the correct answer.
2. We have p(x)=x⁴-2x³-x+2
That is y = x⁴-2x³-x+2
We have coordinates (1,0), substituting
y = 1⁴-2 x 1³-1+2 = 0
So when we are substituting x value as 1 we are getting y as zero, so the point lies in curve.