The area of a square garden is 9ft. How long is each side of the garden

Mrs. McCormick asked students to track the number of times they referred to their planner to check for assignment details during

borishaifa [10]

Answer:

B

Step-by-step explanation:

the answer is b because the they are only 5 numbers of student that check in for assignment details

6 0

3 years ago

No links please :(

kotegsom [21]

A.

Store A has sold the most wristbands

5 0

3 years ago

Question 9: Please help, what would be the length of the image of the segment GH?

shepuryov [24]

Answer:

The length of the image of the segment GH would be 5 units.

Explanation:

You can use the center of dilation as your origin of coordintes.

Thus, the point H would have coordinates (0,0) and the point G (-1,0).

A dilation multiplies the coordinates by the scale factor. Hence:

H = (0,0) → H' = 5 × (0,0) = (0,0)

G = (-1,0) → G] = 5 × (-1, 0) = (-5, 0)

Thus, the length of the image of segment GH would be the distance from 0 to -5 in a number line, which is 5.

3 0

3 years ago

Read 2 more answers

A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

Answer-

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

Solution-

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

$\binom{33}{6} = \frac{33!}{6!27!} =1107568$

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

$\binom{52}{9} = \frac{52!}{9!43!} = 3679075400$

∴P(3 white candies) = $\frac{1073233392}{3679075400} =0.29$

Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

$\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}$

$=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})$

$=(969)(45)(7)(5)(15)=22892625$

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

$\binom{52}{9}=\frac{52!}{9!43!} =3679075400$

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

$\frac{22892625}{3679075400} = 0.006$

6 0

4 years ago

ONE GEOMETRY QUESTION

kondor19780726 [428]

Answer:

c

Step-by-step explanation:

8 0

3 years ago