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jenyasd209 [6]
4 years ago
7

Kepler modified Copernicus's model of the universe by proposing that the A. Planets follow a circular orbit around the sun. B. P

aths of the planets follow an elliptical orbit around the sun. C. Planets have their own orbits around themselves as they orbit the sun. D. Planets follow an elliptical orbit every leap year.
Physics
2 answers:
lisabon 2012 [21]4 years ago
5 0

Answer:

I believe the answer is B, the paths of the planets follow an elliptical orbit around the sun.

tresset_1 [31]4 years ago
4 0

Answer:

B. Paths of the planets follow an elliptical orbit around the sun.

Explanation:

As per Copernicus model of the universe he explained that all planets revolves around the sun in circular orbit with sun at the center of the of the path.

Now as per his theory Radius of orbit of all planets are different and the centripetal force provided by the sun for the circular path of the planets

Now as per his theory all planets must have to move with uniform speed around the sun but this was not true as we can see that the speed of all planets are different at different positions.

So here in order to correct his theory Kepler gives his law of planetary motion that all planets revolves around the sun in elliptical orbit with position of sun as one of its focus.

This path verify all the experimental results of planetary motion and hence correct answer will be

B. Paths of the planets follow an elliptical orbit around the sun.

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The Achilles tendon, which connects the calf muscles to the heel, is the thickest and strongest tendon in the body. In extreme a
Tanzania [10]

Answer:

1) tensile stress = 76.648 Mpa

2) extension = 0.0215 m

Explanation:

Detailed explanation and calculation is shown in the image below

5 0
4 years ago
Which value is most likely to be the pH of a salt that is formed by the reaction of a strong acid and a weak base?
Mice21 [21]
In a hydrolysis reaction between a strong acid and a weak base, the salt formed will have a pH less than 7. By virtue of this phenomenon between <span>weak bases and strong acids</span>, the anion of the strong acid will fail to attract the hydrogen ion<span>, while the cation from the weak base will donate a </span>proton<span> to the water forming a hydronium ion</span><span>.
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7 0
3 years ago
Which is the phase change in which a substance changes from a gas to liquid?
Aleksandr [31]

Answer:

Condensation

Explanation:

The phase change in which a substance changes from a gas to liquid is Condensation.

There are  3 natural states of matter;

Solids, Liquids, and Gases.

Matter under certain conditions can change from one state to another. When Solids are heated they change into Liquids through the process of Heating. Upon cooling, the Liquids convert to Solid through freezing. When a Liquid such as water is heated, it converts into the Gaseous state through evaporation. Upon cooling, the Gas converts back into the Liquid state through Condensation.

3 0
3 years ago
two resistors of 20 ohm each are connected in a parallel with a battery of 10V. The total current passing through circuit is
Varvara68 [4.7K]

Answer:

1 Ampere.

Explanation:

From the question given above, the following data were obtained:

Resistor 1 (R₁) = 20 ohm

Resistor (R₂) = 20 ohm

Voltage (V) = 10 V

Current (I) =?

Next, we shall determine the equivalent resistance in the circuit. This can be obtained as follow:

Resistor 1 (R₁) = 20 ohm

Resistor (R₂) = 20 ohm

Equivalent Resistance (R) =?

Since the resistors are in parallel connection, the equivalent resistance can be obtained as follow:

R = (R₁ × R₂) / (R₁ + R₂)

R = (20 × 20) / (20 + 20)

R = 400 / 40

R = 10 ohm

Finally, we shall determine the total current in the circuit. This can be obtained as illustrated below:

Voltage (V) = 10 V

Equivalent Resistance (R) = 10 ohm

Current (I) =?

V = IR

10 = I × 10

Divide both side by 10

I = 10 / 10

I = 1 Ampere

Therefore, the total current in the circuit is 1 Ampere.

3 0
3 years ago
Chapter 36, Problem 007 Light of wavelength 586 nm is incident on a narrow slit. The angle between the first diffraction minimum
svp [43]

Answer:

d =4.77\times 10^{-5}\ m

Explanation:

given

wavelength of light  λ = 479 nm

                                   = 479 x 10⁻⁹ m

the angle

θ = 1.15 / 2 = 0.575°                

using                                              

condition for diffraction minimum ,

         d sinθ = m λ                        

for first minimum m = 1

       d sinθ = λ                      

therefore ,

slit width                                  

d =\dfrac{\lambda}{sin\theta}          

d =\dfrac{479\times 10^{-9}}{sin 0.575^0}

d =\dfrac{479\times 10^{-9}}{0.01}              

d =4.77\times 10^{-5}\ m                                                    

hence, the width of the slit is equal to d =4.77\times 10^{-5}\ m

3 0
3 years ago
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