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AlexFokin [52]
4 years ago
7

Find the x-components of this vector: 92.5 m, 32.0 degrees. Remember, angles are measured from the +x axis.

Physics
1 answer:
Brrunno [24]4 years ago
3 0

Answer:78.44\ m

Explanation:

Given

magnitude of vector =92.5\ m

vector makes an angle of \theta =32^{\circ} with x-axis

Vector can be resolved into two components i.e. vertical and horizontal

Horizontal component along x-axis=92.5\cos 32

=78.44\ m

along the negative x-axis

justhereforanswers
3 years ago
sooo is the answer -78.44?
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When energy is added to a fl uid, the temperature of the fl uid increases. an equation describing this phenomenon is:_________
Ksju [112]

The temperature of a fluid rises when energy is given to it. This phenomenon can be described by the equation:

Q = MCp ΔT

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Q is the quantity of added energy.

M is the fluid's mass.

The fluid's heat capacity is denoted by Cp.

T stands for temperature change.

<h3>What happens to a fluid's kinetic energy as the temperature rises?</h3>

The mean kinetic energy of the particles in a liquid rises with temperature. The molecules' higher average kinetic energies allow them to more easily overcome the attraction forces that keep them bound together.

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The most significant determining factor for fluidity is pouring temperature. Therefore, the fluidity increases as the pouring temperature increases.

<h3>How does a liquid react when the temperature rises?</h3>

Particles in a solid, liquid, or gas move more quickly as its temperature rises. The particles slow down as the temperature drops. When a liquid is sufficiently cooled, it turns into a solid.

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6 0
2 years ago
Someone solvw this for me please
soldi70 [24.7K]

The velocity of the mass at time, t = 1 s, is determined as 20 m/s.

<h3>Magnitude of the force experienced by the body</h3>

The magnitude of the force experienced by the body is calculated as follows;

|F| = √(8² + 6²)

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6 0
2 years ago
Anna Litical is studying the periodic motion of a 1.04-m long pendulum in The Wiggles lab on Earth. What period can Anna expect
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3 0
1 year ago
hot water is added to three times its mass of water at 10 degree celsius and the resulting temperature is 20 degrees Celsius Wha
olchik [2.2K]

Answer:

The initial temperature of the hot water is 50\; \rm ^{\circ} C (assuming that no heat was lost to the surroundings.)

Explanation:

Let m denote the mass of the hot water.

The question states that the mass of the water at 10\; \rm ^\circ C is three times the mass of the hot water. If the mass of the hot water is m, the mass of the cold water would be 3\, m.

Let c denote the specific heat capacity of water. Let m denote the mass of some water. The energy required to change the temperature of that much water by \Delta T (without state change) would be:

Q = c \cdot m \cdot \Delta T.

The temperature change for the cold water was:

\Delta T_1 = 20\; \rm ^{\circ} C - 10\; \rm ^{\circ} C = 10\; \rm K.

Energy required to raise the temperature of water with mass 3\, m from 10\; \rm ^{\circ} C to 20\; \rm ^{\circ} C:

Q_1 = c \cdot (3\, m) \cdot (10\; \rm K).

On the other hand, if the initial temperature of the hot water is t\; \rm ^{\circ} C (where t > 20,) the temperature change would be:

\Delta T_2 = t\; {\rm ^{\circ} C} - 20\; {\rm ^{\circ} C} = (t - 20)\; {\rm K}.

Calculate the energy change involved:

Q_2 = c \cdot m \cdot ((t - 20)\; \rm K).

If no energy was lost to the surroundings, Q_1 should be equal to Q_2. That is:

c \cdot (3\, m) \cdot (10\; {\rm K}) = c\cdot m \cdot ((t - 20)\; {\rm K}).

Simplify and solve for t:

t - 20 = 30.

t = 50.

Therefore, the initial temperature of the hot water would be 50\; {\rm ^\circ C}.

6 0
3 years ago
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