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katen-ka-za [31]

3 years ago

11

A football is kicked with a velocity of 31 meters per second at an angle of 41 degrees what is the balls acceleration in the ver

tical direction as it flies through the air

2 answers:

IgorC [24]3 years ago

8 0

Answer:

The vertical component of the acceleration is equal to the acceleration due to gravity g.

Explanation:

Given data,

The initial velocity of the football, u = 31 m/s

The angle of direction of the football with the horizontal, Ф = 41°

In free fall, the vertical component of acceleration always remains the same.

Since the ball is clicked in a particular direction that has a vertical component, then the vertical component of the velocity of the ball is always acted upon by the gravitational force of the earth.

The horizontal component of the velocity of the projectile remains the same because the gravitational force doesn't act in the horizontal direction.

Since the only force is the gravitational force acts on the projectile, the vertical component of the acceleration is equal to the acceleration due to gravity g.

BaLLatris [955]3 years ago

8 0

Answer:

-9.8 m/s^2

Explanation:

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Answer:

Deductive

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The question bases the conclusion on the premise that the Big Bang theory which is based on scientific evidence is several billions of years old and if the theory is correct the universe <em>(as it is today)</em> was not created six days

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A kid on a trampoline has 1,000 J of potential energy when they are at the top of a jump. How much kinetic energy will the kid h

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7 0

2 years ago

Two scales on a nondigital voltmeter measure voltages up to 20.0 and 30.0 V, respectively. The resistance connected in series wi

Snowcat [4.5K]

Answer:

Resistance of the circuit is 820 Ω

Explanation:

Given:

Two galvanometer resistance are given along with its voltages.

Let the resistance is "R" and the values of voltages be 'V' and 'V1' along with 'G' and 'G1'.

⇒ $V=20\ \Omega,\ V_1=30\ \Omega$

⇒ $G=1680\ \Omega,\ G_1=2930\ \Omega$

Concept to be used:

Conversion of galvanometer into voltmeter.

Let $G$ be the resistance of the galvanometer and $I_g$ the maximum deflection in the galvanometer.

To measure maximum voltage resistance $R$ is connected in series .

So,

⇒ $V=I_g(R+G)$

We have to find the value of $R$ we know that in series circuit current are same.

For $G=1680$ For $G_1=2930$

⇒ $I_g=\frac{V}{R+G}$ equation (i) ⇒ $I_g=\frac{V_1}{R+G_1}$ equation (ii)

Equating both the above equations:

⇒ $\frac{V}{R+G} = \frac{V_1}{R+G_1}$

⇒ $V(R+ G_1) = V_1 (R+G)$

⇒ $VR+VG_1 = V_1R+V_1G$

⇒ $VR-V_1R = V_1G-VG_1$

⇒ $R(V-V_1) = V_1G-VG_1$

⇒ $R =\frac{V_1G-VG_1}{(V-V_1)}$

⇒ Plugging the values.

⇒ $R =\frac{(30\times 1680) - (20\times 2930)}{(20-30)}$

⇒ $R =\frac{(50400 - 58600)}{(-10)}$

⇒ $R=\frac{-8200}{-10}$

⇒ $R=820\ \Omega$

The coil resistance of the circuit is 820 Ω .

4 0

3 years ago

A cricket starts at the 5 meter mark on a ruler. It jumps to the 10 meter mark. Then, it jumps back to the 6 meter mark. Calcula

belka [17]

We have that the cricket’s displacement is

$D_t=9meters$

From the Question we are told that

Start position 5 meter mark

It jumps to the 10 meter mark.

it jumps back to the 6 meter mark.

Generally the equation for cricket’s displacement. is mathematically given as

$D_t=Initial +final(displacement)\\\\D_t=(10-5)+(10-6)$

$D_t=9meters$

For more information on this visit

brainly.com/question/24273210?referrer=searchResults

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3 years ago

What caused the big bang? WILL UPVOTE!!!

kvasek [131]

The expansion of the observable universe began <span>with the explosion of a single particle at a definite point in time.</span>

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3 years ago