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satela [25.4K]
4 years ago
11

Which equation best describes the law of conservation of momentum?

Physics
2 answers:
NeX [460]4 years ago
8 0
The law of conservation of momentum<span> states that for two objects colliding in an isolated system, the total </span>momentum<span> before and after the collision is equal. Momentum should be conserved. Hope this answers the question. Have a nice day.</span>
allochka39001 [22]4 years ago
6 0

Answer:

pi = pf

Explanation:

its the equation

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what is the magnitude of the gravitational force acting on the earth due to the sun? express your answer in newtons.
Alborosie

The gravitational force the sun experiences from the earth is 3.48×10²²N, which is exactly the same as the force the sun experiences from the earth.

  • Gravity is a force that develops as a result of the attraction between mass-containing objects. The mass of the object has a direct relationship to the strength of this attraction. r equals the separation of two objects.

F = G (M₁M₂)/r²

Where, F  the gravitational force

G=6.67×10⁻¹¹Nm²kg⁻² gravitational constant

M₁=5.98×10²⁴kg  mass of earth

M₂= 1.99×10³⁰ kg the mass of the sun

r =15×10¹⁰ m is the distance between sun and earth

Putting all the values in above equation,

F = 6.67×10⁻¹¹Nm²kg⁻²(5.98×10²⁴kg 1.99×10³⁰ kg)/15×10¹⁰ m

On solving the above equation we get,

F = 3.48×10²²N

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1 year ago
A rising pendulum bob gains _____ energy.
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B. Kinetic energy.............

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The farthest major planet from the sun is
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The farthest major planet from the sun is Neptune

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Optics Quiz<br><br> can somebody please help me!
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Answer:

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3 years ago
1.
Ivenika [448]

The ant's resultant velocity is 0.51 m/s at 78.7°

Since the ant is moving with a velocity of 0.1 m/s in the +x direction relative to the treadmill, and the treadmill is moving 0.5 m/s in the +y direction, the magnitude of the resultant velocity of the ant relative to the ground (since both directions are perpendicular) is thus

V = √(x² + y²)

= √[(0.1 m/s)² + (0.5 m/s)²]

= √[0.01 m²/s² + 0.25 m²/s²]

= √(0.26 m²/s²)

= 0.51 m/s.

The direction is Ф = tan⁻¹(y/x)

= tan⁻¹(0.5 m/s ÷ 0.1 m/s)

= tan⁻¹(5)

= 78.69°

≅ 78.7°

The ant's resultant velocity is 0.51 m/s at 78.7°

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