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3 years ago

12

How can the rate of a reaction be increased?

2 answers:

OlgaM077 [116]3 years ago

7 0

The Answer Is Lowering the amount of reactants

yuradex [85]3 years ago

7 0

Answer:

C. Having more surface area

When the reaction involves solids, an increased surface area of it will result in an increased reaction rate. The <em>higher</em> the temperature, the faster the reaction rate will be too. Lowering the temperature, decreasing the amount of reactions, and diluting a solution will decrease the reaction rate

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What is a conversion factor?

rosijanka [135]

Answer:

A ratio of equivalent units

Explanation:

A conversion factor is a ratio of equivalent units and depends on which units are to be converted.

For example we want to convert 275 [mm] to inches, so we have to find the right conversion factor to allow us to work that conversion.

275 [mm] = inches = ?

$275 [mm] * \frac{1in}{25.4mm} = 10.82 [in]$

In this case the ratio is 1/25.4 = 0.039 [in/mm]

4 0

3 years ago

The velocity of a particle moving along the x-axis varies with time according to v(t) = A + Bt−1 , where A = 2 m/s, B = 0.25 m,

kondaur [170]

Answer:

$a= -2\ m/s^2$

$a=-12.5\ m/s^2$

x=2.17 m

x=8.4 m

Explanation:

Given that

$v=A+Bt^{-1}$

$v=2+0.25t^{-1}$

To find acceleration :

we know that

$a=\dfrac{dv}{dt}$

$\dfrac{dv}{dt}=0-0.5t^{-2}$

$a=-0.5t^{-2}$

Acceleration at t= 2 s

$a=-0.5\times 2^{-2}$

$a= -2\ m/s^2$

Acceleration at t= 5 s

$a=-0.5\times 5^{-2}$

$a=-12.5\ m/s^2$

We know that

$v=\dfrac{dx}{dt}$

$dx=\left(2+\dfrac{1}{4t}\right)dt$

Position at t= 2 s:

$\int_{0}^{x}dx=\int_{1}^{2} \left(2+0.25\dfrac{1}{t}\right)dt$

$x=\left [2t+0.25\ lnt \right ]_{1}^{2}$

x=2+0.25 ln2

x=2.17 m

Position at t= 5 s:

$\int_{0}^{x}dx=\int_{1}^{5} \left(2+0.25\dfrac{1}{t}\right)dt$

$x=\left [2t+0.25\ lnt \right ]_{1}^{5}$

x=8+0.25 ln5

x=8.4 m

4 0

3 years ago

Dr. Suwary runs really fast. She is in a race and is running at 50 m/s. Dr. Suwary's enemy is

Ivenika [448]

Answer: 120 m/s?

Explanation:

3 0

3 years ago

Evidence suggests that there may be _______ momentum and ________ reversal patterns in stock price behavior.

bearhunter [10]

CORRECT ANSWER:

D. short-run; long run

STEP-BY-STEP EXPLANATION:

The whole question from book is

Evidence suggests that there may be _______ momentum and ________ reversal patterns in stock price behavior.

A. short-run; short-run

B. long-run; long-run

C. long-run; short-run

D. short-run; long run

Evidence suggests that there may be <em><u>short-run</u></em> momentum and <em><u>long run </u></em>reversal patterns in stock price behavior.

8 0

3 years ago

Pre-Test Active

vlada-n [284]

n is the answer I guess

not so sure

7 0

2 years ago