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Artist 52 [7]
3 years ago
12

How can the rate of a reaction be increased?

Physics
2 answers:
OlgaM077 [116]3 years ago
7 0

The Answer Is Lowering the amount of reactants

yuradex [85]3 years ago
7 0

Answer:

C. Having more surface area

When the reaction involves solids, an increased surface area of it will result in an increased reaction rate. The <em>higher</em> the temperature, the faster the reaction rate will be too. Lowering the temperature, decreasing the amount of reactions, and diluting a solution will decrease the reaction rate

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What is a conversion factor?
rosijanka [135]

Answer:

A ratio of equivalent units

Explanation:

A conversion factor is a ratio of equivalent units and depends on which units are to be converted.

For example we want to convert 275 [mm] to inches, so we have to find the right conversion factor to allow us to work that conversion.

275 [mm] = inches = ?

275 [mm] * \frac{1in}{25.4mm} = 10.82 [in]

In this case the ratio is 1/25.4 = 0.039 [in/mm]

4 0
3 years ago
The velocity of a particle moving along the x-axis varies with time according to v(t) = A + Bt−1 , where A = 2 m/s, B = 0.25 m,
kondaur [170]

Answer:

a= -2\ m/s^2

a=-12.5\ m/s^2

x=2.17 m

x=8.4 m

Explanation:

Given that

v=A+Bt^{-1}

v=2+0.25t^{-1}

To find acceleration :

we know that

a=\dfrac{dv}{dt}

\dfrac{dv}{dt}=0-0.5t^{-2}

a=-0.5t^{-2}

Acceleration at t= 2 s

a=-0.5\times 2^{-2}

a= -2\ m/s^2

Acceleration at t= 5 s

a=-0.5\times 5^{-2}

a=-12.5\ m/s^2

We know that

v=\dfrac{dx}{dt}

dx=\left(2+\dfrac{1}{4t}\right)dt

Position at t= 2 s:

\int_{0}^{x}dx=\int_{1}^{2} \left(2+0.25\dfrac{1}{t}\right)dt

x=\left [2t+0.25\ lnt \right ]_{1}^{2}

x=2+0.25 ln2

x=2.17 m

Position at t= 5 s:

\int_{0}^{x}dx=\int_{1}^{5} \left(2+0.25\dfrac{1}{t}\right)dt

x=\left [2t+0.25\ lnt \right ]_{1}^{5}

x=8+0.25 ln5

x=8.4 m

4 0
3 years ago
Dr. Suwary runs really fast. She is in a race and is running at 50 m/s. Dr. Suwary's enemy is
Ivenika [448]

Answer: 120 m/s?

Explanation:

3 0
3 years ago
Evidence suggests that there may be _______ momentum and ________ reversal patterns in stock price behavior.
bearhunter [10]

CORRECT ANSWER:

D. short-run; long run

STEP-BY-STEP EXPLANATION:

The whole question from book is

Evidence suggests that there may be _______ momentum and ________ reversal patterns in stock price behavior.

A. short-run; short-run

B. long-run; long-run

C. long-run; short-run

D. short-run; long run

Evidence suggests that there may be <em><u>short-run</u></em> momentum and <em><u>long run </u></em>reversal patterns in stock price behavior.

8 0
3 years ago
Pre-Test Active
vlada-n [284]

n is the answer I guess

not so sure

7 0
2 years ago
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