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Rasek [7]
2 years ago
11

Explain what concave and convex mirrors do to parallel rays directed to their surfaces.​

Physics
1 answer:
dezoksy [38]2 years ago
7 0

Answer:

the man who are you support Russia and your birthdayto is made by the day is in Today Android of the world ye hai song

Explanation:

there are not false and your family is not a well of you and you t are

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How fast would you be going (in kmh) if you had a ship that accelerated at a constant 1g for 24 hours?
Nady [450]

Answer:

Explanation:

1 g is 9.8 m/s^2 the problem wants the results in km/h so we'll fix that really quick.

9.8 m/s^2 (1 km/1000m)(60 sec/1 min)^2(60 min/1 hour)^2 = 127008 km/hour^2

Now, I'm assuming the ship is starting from rest, and hopefully you know your physics equations.  We are going to use vf = vi + at.  Everything is just given, or we can assume, so I'll just solve.

vf = vi + at

vf = 0 + 127008 km/hour^2 * 24 hours

vf = 3,048,192 km/hour

If there's anything that doesn't make sense let me know.  

5 0
3 years ago
The question is on the picture
Firlakuza [10]

Answer:

<em> think 2 also if not im so sorry  but i think it is :)</em>

7 0
2 years ago
A spectroscope prism separates the white light from a star into a very wide spectrum. When widely spread, black lines appear in
topjm [15]

Answer:

C. It helps scientists detect dark matter.

Explanation:

I got a 100% on my test. hope it help and I hope your having an awesome day :)

5 0
3 years ago
Read 2 more answers
Help with 1 2 and 3 please
geniusboy [140]

1. Amperes, is the SI unit (also a fundamental unit) responsible for current.

2. I = \frac{q}{t} Δq over Δt technically

Rearrange for Δq

I x Δt = Δq

1.5mA x 5 = Δq

Δq = 0.0075

Divide this by the fundamental charge "e"

Electrons: 0.0075 / 1.60 x 10^-19

Electrons: 4.6875 x 10^16 or 4.7 x 10^16

3.  So we know that the end resistances will be equal so:

ρ = RA/L

ρL = RA

ρL/A = R

Now we can set up two equations one for the resistance of the aluminum bar and one for the copper: Where 1 represents aluminum and 2 represents copper

\frac{p1L1}{A1}  = \frac{p2L2}{A2}\\

We are looking for L2 so we can isolate using algebra to get:

\frac{A2(\frac{P1L1}{A1}) }{P2} = L2

If you fill in those values you get 0.0205

or 2.05 cm



6 0
3 years ago
Recall that the blocks can only move along the x axis. the x components of their velocities at a certain moment are v1x and v2x.
Contact [7]
The center of mass is given with this formula:
x_c=\frac{\sum_{n=1}^{n=i}m_ix_i}{M}
Velocity is:
v=\frac{dv}{dt}
So, for the velocity of the center of mass we have:
\frac{dx_c}{dt}=\frac{\sum_{n=1}^{n=i}d(m_ix_i)}{Mdt}\\&#10;v_c=\frac{\sum_{n=1}^{n=i}p_i}{M}\\
In our case it is:
v_{xc}=\frac{m_1v_{x1}+m_2v_{x2}}{m_1+m_2}
 
5 0
3 years ago
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