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Rasek [7]
2 years ago
11

Explain what concave and convex mirrors do to parallel rays directed to their surfaces.​

Physics
1 answer:
dezoksy [38]2 years ago
7 0

Answer:

the man who are you support Russia and your birthdayto is made by the day is in Today Android of the world ye hai song

Explanation:

there are not false and your family is not a well of you and you t are

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2. The water is then heated to its boiling point. Calculate the specific latent heat of
Law Incorporation [45]

Answer:

2465 J/g

Explanation:

The amount of energy required to boil a sample of water already at boiling point is given by

Q=m\lambda_v

where

m is the mass of the water sample

\lambda_v is the specific latent heat of vaporization of water

In this problem, we know

Q=813,600 J

m = 330 g

Solving the equation for \lambda_v, we find

\lambda_v = \frac{Q}{m}=\frac{813600}{330}=2465 J/g

6 0
3 years ago
Which best describes the way a sound wave is sent through the radio?
Anna35 [415]

Answer:

sound wave-electrical wave-radio wave

4 0
3 years ago
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At a certain point in space, there is a potential of 800 V relative to zero. What is the potential energy of the system when a +
sammy [17]

To solve this problem we will apply the concepts related to electric potential and electric potential energy. By definition we know that the electric potential is determined under the function:

V = \frac{k_e q}{r}

k_e = Coulomb's constant

q = Charge

r = Radius

At the same time

U = \frac{k_e q_1q_2}{r}

The values of variables are the same, then if we replace in a single equation we have this expression,

U  = Vq

If we replace the values, we have finally that the charge is,

V = 800V

q = 1\mu C

U = (800V)(1*10^{-6}C)

U = 8*10^{-4}J

Therefore the potential energy of the system is 8*10^{-4} J

7 0
3 years ago
1. An object moving with velocity 15 ms accelerates at 2 m/s for 5 seconds. Calculate the final velocity.​
DedPeter [7]

Answer:

final velocity=u+at 15+2×5=25

7 0
2 years ago
78. A film of oil on water will appear dark when it is very thin, because the path length difference becomes small compared with
Hoochie [10]

To solve this problem it is necessary to apply the concepts related to the condition of path difference for destructive interference between the two reflected waves from the top and bottom of a surface.

Mathematically this expression can be described under the equation

\delta = 2nt

Where

n = Refractive index

t = Thickness

In terms of the wavelength the path difference of the reflected waves can be described as

\delta = \frac{\lambda}{4}

Where

\lambda = Wavelenght

Equation the two equations we have that

2nt = \frac{\lambda}{4}

t = \frac{\lambda}{8n}

Our values are given as

\lambda = 380nm \rightarrow Wavelength of light

n = 1.4

t = \frac{380nm}{8*1.4}

t = 33.93nm

Therefore the minimum thickness of the oil for destructive interference to occur is approximately 34.0 nm

4 0
3 years ago
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