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rewona [7]
3 years ago
10

As the wavelength of electromagnetic radiation increases. true or false

Physics
1 answer:
KIM [24]3 years ago
7 0

Answer:

Explanation:

The energy and the frequency of electromagnetic radiation inversely proportional to the frequency of radiation.

So, as the wavelength increases, the energy and the frequency decreases.

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A string is wrapped several times around the rim of a small hoop with radius 8.00 cm and mass 0.180 kg. The free end of the stri
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Answer:

(a). The angular speed of the rotating is 33.8 rad/s.

(b). The speed of its center is 2.7 m/s.

Explanation:

Given that,

Radius = 8.00 cm

Mass = 0.180 kg

Height = 75.0 m

We need to calculate the angular speed of the rotating

Using conservation of energy

\dfrac{1}{2}I\omega_{1}^2+\dfrac{1}{2}mv_{1}^{2}+mgh_{1}=\dfrac{1}{2}I\omega_{2}^2+\dfrac{1}{2}mv_{2}^{2}+mgh_{2}

Here, initial velocity and angular velocity are equal to zero.

mgh_{1}=\dfrac{1}{2}I\omega_{2}^2+\dfrac{1}{2}mv_{2}^{2}+mgh_{2}

mg(h_{1}-h_{2})=\dfrac{1}{2}I\omega_{2}^2+\dfrac{1}{2}mv_{2}^{2}

mgH=\dfrac{1}{2}mr^2\omega_{2}^2+\dfrac{1}{2}m(r\omega_{2})^2

Here, H = h_{1}-h_{2}

gH=r^2\omega_{2}^2

\omega_{2}^2=\dfrac{gH}{r^2}

\omega_{2}=\sqrt{\dfrac{9.8\times75.0\times10^{-2}}{(8.00\times10^{-2})^2}}

\omega_{2}=33.8\ rad/s

The angular speed of the rotating is 33.8 rad/s.

(b). We need to calculate the speed of its center

Using formula of speed

v=r\omega

Put the value into the formula

v=8.00\times10^{-2}\times33.8

v=2.7\ m/s

Hence, (a). The angular speed of the rotating is 33.8 rad/s.

(b). The speed of its center is 2.7 m/s.

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3 years ago
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