The range of the function is {-34, -2, -20}
<h3>How to determine the range?</h3>
The function is given as:
f(x) = -2x^2 - 2
The domain is {-4, 0, 3}
Substitute the domain values in the function.
f(-4) = -2(-4)^2 - 2 = -34
f(0) = -2(0)^2 - 2 = -2
f(3) = -2(3)^2 - 2 = -20
This means that the range of the function is {-34, -2, -20}
Read more about range at:
brainly.com/question/10197594
#SPJ1
I would assume that the answer would be x=40 degrees, if not that then x=50 degrees but I would answer with x=40 degrees.
Answer
C but then again i might be wrong
Answer:
a=-2î+j-5k
|a| = √(−2)² +1² + (−5)²
a = √√4+1+25
a = √30
Thus, direction cosines of a are
(- 2/(sqrt(30)), 1/(sqrt(30)), - 5/(sqrt(30)))
Answer:
5. 9 8. 
Step-by-step explanation:
a²+b²=c²
so for #5 12²+b²=15²
144+b²=225 (subtract 144 from both sides)
b²=81
b=9
For #8
9²+b²=11²
81+b²=121 (subtract 81 from both sides)
b²=40
b=
=
