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3 years ago

Can someone help me on 2 science question,

2 answers:

8 0

1. I think you should compare diagrams of moon phases from the textbook to diagrams of moon phases online. Because if you pick D it will take to long and C will help you out whith 3 different things to look at.

2. The moon changes in appearances from the perspective of people on earth because it's revolving around the planet and the earth is revolving around the sun, so A. Hoped this helped.

Amiraneli [1.4K]3 years ago

7 0

For question 1, I would go with option B. This is how science works. You start off with a hypothesis and then you test to see if what you observe matches the hypothesis. For option A, you risk not getting complete data. If the night you pick to start happens to be a full moon, you're done before you start. Option C is only comparing one set of stated facts against another set of stated facts. You have to trust these at face value. Both could be wrong. Option D says "as often as possible" which is too vague. If it was every night, then you would have your evidence six times over. If you can only test every 28th day, then you're going to see the same phase of the moon each time.

Question 2: The answer is B. The moon revolves around the Earth. As the Moon orbits the Earth, it is in a different part of the sky with relation to the Sun. When the Moon is fully behind the Earth, the Sun shines straight on and we see a full moon. When the moon is between the Earth and the Sun the light from the Sun falls on the side farthest away from the Earth and so we don't see it.
Here is a diagram to illustrate
http://www.moonconnection.com/images/moon_phases_diagram.jpg

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A 6.9-kg wheel with geometric radius m has radius of gyration computed about its mass center given by m. A massless bar at angle

Vilka [71]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is $\alpha =2.538 \ rad/s^2$

Explanation:

From the question we are told that

The mass of the wheel is m = 6.9 kg

The radius is $r = 0.69 \ m$

The radius of gyration is $k_G = 0.4\ m$

The angle is $\theta = 47^o$

The force which the massless bar is subjected to $F = 22.5 \ N$

Generally given that the wheels rolls without slipping on the flat stationary ground surface, it implies that point A is the center of rotation.

Generally the moment of inertia about A is mathematically represented as

$I_a = I_G + M* r^2$

Here $I_G$ is the moment of inertia about G with respect to the radius of gyration which is mathematically represented as

$I_G = M * k_G$

=> $I_a = k_G* M + M* r^2$

=> $I_a =0.4 * 6.9 + 6.9 * 0.69^2$

=> $I_a =6.045 \ kg \cdot m^2$

Generally the torque experienced by the wheel is mathematically represented as

$\tau = F * cos (47)$

=> $\tau = 22.5 * cos (47)$

=> $\tau = 15.34 \ kg \cdot m^2 \cdot s^{-2}$

Generally this torque is also mathematically represented as

$\tau = I_a * \alpha$

=> $15.34 = 6.045 * \alpha$

=> $\alpha =2.538 \ rad/s^2$

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3 years ago

Convert 592 minutes to seconds. using one step conversion.

vovangra [49]

Answer:

35520

Explanation:

592 times 60=35520

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3 years ago

What is the value of relative humidity when the air is saturated?

Brut [27]

Answer:

100 percent

Explanation:

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3 years ago

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Ratling [72]

Answer:

89.5 Hz

Explanation:

The relationship between the frequency and the wavelength is given by the following formula:

$\lambda = \frac{c}{f}\\\\$

where,

f = frequency

c = speed of light

λ = wavelength

Since the speed of light is constant. Therefore the formula suggests an inverse relationship between the frequency and the wavelength. Hence, the station with the lowest frequency will have the longest wavelength.

Therefore, the answer is:

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3 years ago

HELP!!!!!!!!!

WARRIOR [948]

I think it would be A
hope this helps.
A and C

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3 years ago