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3 years ago

Can someone help me on 2 science question,

2 answers:

8 0

1. I think you should compare diagrams of moon phases from the textbook to diagrams of moon phases online. Because if you pick D it will take to long and C will help you out whith 3 different things to look at.

2. The moon changes in appearances from the perspective of people on earth because it's revolving around the planet and the earth is revolving around the sun, so A. Hoped this helped.

Amiraneli [1.4K]3 years ago

7 0

For question 1, I would go with option B. This is how science works. You start off with a hypothesis and then you test to see if what you observe matches the hypothesis. For option A, you risk not getting complete data. If the night you pick to start happens to be a full moon, you're done before you start. Option C is only comparing one set of stated facts against another set of stated facts. You have to trust these at face value. Both could be wrong. Option D says "as often as possible" which is too vague. If it was every night, then you would have your evidence six times over. If you can only test every 28th day, then you're going to see the same phase of the moon each time.

Question 2: The answer is B. The moon revolves around the Earth. As the Moon orbits the Earth, it is in a different part of the sky with relation to the Sun. When the Moon is fully behind the Earth, the Sun shines straight on and we see a full moon. When the moon is between the Earth and the Sun the light from the Sun falls on the side farthest away from the Earth and so we don't see it.
Here is a diagram to illustrate
http://www.moonconnection.com/images/moon_phases_diagram.jpg

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Black_prince [1.1K]

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Solar system is a part of Milkyway Galaxy.

Explanation:

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3 years ago

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You are observing the radiation from a distant active galaxy and you notice that the amplitude of the signal varies in strength

GREYUIT [131]

Answer:

Period of the signal.

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3 years ago

The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, in

bezimeni [28]

1) Potential difference: 1 V

2) $V_b-V_a = -1 V$

Explanation:

When a charge moves in an electric field, its electric potential energy is entirely converted into kinetic energy; this change in electric potential energy is given by

$\Delta U=q\Delta V$

where

q is the charge's magnitude

$\Delta V$ is the potential difference between the initial and final position

In this problem, we have:

$q=4.80\cdot 10^{-19}C$ is the magnitude of the charge

$\Delta U = 4.80\cdot 10^{-19}J$ is the change in kinetic energy of the particle

Therefore, the potential difference (in magnitude) is

$\Delta V=\frac{\Delta U}{q}=\frac{4.80\cdot 10^{-19}}{4.80\cdot 10^{-19}}=1 V$

Here we have to evaluate the direction of motion of the particle.

We have the following informations:

- The electric potential increases in the +x direction

- The particle is positively charged and moves from point a to b

Since the particle is positively charged, it means that it is moving from higher potential to lower potential (because a positive charge follows the direction of the electric field, so it moves away from the source of the field)

This means that the final position b of the charge is at lower potential than the initial position a; therefore, the potential difference must be negative:

$V_b-V_a = - 1V$

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2 years ago

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sleet_krkn [62]

Answer:

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lawyer [7]

It's D i'm pretty sure

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