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____ [38]
3 years ago
9

Can someone help me on 2 science question,

Physics
2 answers:
gavmur [86]3 years ago
8 0
1. I think you should compare diagrams of moon phases from the textbook to diagrams of moon phases online. Because if you pick D it will take to long and C will help you out whith 3 different things to look at. 

2. The moon changes in appearances from the perspective of people on earth because it's revolving around the planet and the earth is revolving around the sun, so  A. Hoped this helped.

Amiraneli [1.4K]3 years ago
7 0
For question 1, I would go with option B. This is how science works. You start off with a hypothesis and then you test to see if what you observe matches the hypothesis. For option A, you risk not getting complete data. If the night you pick to start happens to be a full moon, you're done before you start. Option C is only comparing one set of stated facts against another set of stated facts. You have to trust these at face value. Both could be wrong. Option D says "as often as possible" which is too vague. If it was every night, then you would have your evidence six times over. If you can only test every 28th day, then you're going to see the same phase of the moon each time.

Question 2: The answer is B. The moon revolves around the Earth. As the Moon orbits the Earth, it is in a different part of the sky with relation to the Sun. When the Moon is fully behind the Earth, the Sun shines straight on and we see a full moon. When the moon is between the Earth and the Sun the light from the Sun falls on the side farthest away from the Earth and so we don't see it. 
Here is a diagram to illustrate
http://www.moonconnection.com/images/moon_phases_diagram.jpg
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¿Qué cantidad de calor absorbió una masa de 4 g de cinc al pasar de 20 °C a<br> 180 °C?
Alborosie

(amount of heat)Q = ? , (Mass) m= 4 g , ΔT = T f - T i = 180 c° - 20 °c = 160 °c ,

Ce = 0.093 cal/g. °c

Q = m C ΔT

Q = 4 g × 0.093 cal/g.c° × ( 180 °c- 20 °c )

Q= 4×0.093 × 160

Q = 59.52 cal

I hope I helped you^_^

7 0
2 years ago
If a trapezoidal channel has side slopes of 1:1, hydraulic depth is 5 feet, the bottom width is 8 feet, flow is 2,312 cubic feet
Evgesh-ka [11]

Answer:

S = \dfrac{1}{2.5}

Explanation:

given,

side slope = 1 : 1

hydraulic depth(y) = 5 ft

bottom width (b)= 8 ft

x = 1

Q = 2,312 ft³/s

n = 0.013

slope of channel = ?

R = \dfrac{A}{P}

R = \dfrac{y(b + xy)}{b+2y\sqrt{1+x^2}}

R = \dfrac{5(8+ 5)}{8+2\times 5\sqrt{1+1^2}}

R = 4.69 m

using manning's equation

Q = \dfrac{1}{n}AR^{2/3} S^{1/2}

2312= \dfrac{1}{0.013}\times (5(8+5))\times 4.69^{2/3} S^{1/2}

2312=14009.37\times S^{1/2}

S = 0.406

S = \dfrac{1}{2.5}

5 0
3 years ago
During the latter part of your European vacation, you are hanging out at the beach at the gold coast of Spain. As you are laying
adelina 88 [10]

The maximum height attained is 460 m.

<h3>What is the maximum height?</h3>

We know that the final velocity of a body is 0 m/s at the maximum height which is the greatest height that is attained by the body. We now use the formula;

v^2 = u^2 -2gh

Given that v = 0 m/s

u^2 = 2gh

h = u^2/2g

v = final velocity

u = initial velocity

h = maximin height

g = acceleration due to gravity

h = (95)^2/2 * 9.8

h = 460 m

Learn more about maximum height:brainly.com/question/6261898

#SPJ1

6 0
1 year ago
Which of the following describes an action-reaction pair?
Diano4ka-milaya [45]
Answer B is the correct pair.
7 0
3 years ago
A 30-g car rolls from a hill 12 cm high and is traveling at 154 cm/s as it travels along a 275 cm horizontal track. What is the
Bond [772]
Momentum of the car is 46.2 kgm/s
8 0
3 years ago
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