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2 years ago

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Two for are at an angle at 120 ,the bigger forces is 40N and the resultant is perpendicular to the smaller one. find the smaller

force

1 answer:

Nadya [2.5K]2 years ago

3 0

Answer:

smaller force is 20

Explanation:

Let, magnitude of the smaller force be F Newton.

Now, the resultant force makes an angle 90° with the smaller force. So, angle between resultant force and the larger force = (120° - 90°) = 30°.

So, tan 30° = (F * sin 120°) / (40 + F * cos 120°)

(1 / √3) = {F * (√3) / 2} / {40 + F * (- 1 / 2)}

80 - F = 3F

4F = 80

F = 20.

So, magnitude of smaller force is 20 Newtons.

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Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is

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The car A has a mass of 1200 kg.

The car B has the mass of 1900 kg.

It is given that velocity of car A is given as 22 Km/hr

The car B has the velocity of 25 Km/hr.

Let the mass of two bodies are denoted as $m_{1} \ and\ m_{2}$

Let the velocity of cars A and B are denoted as $v_{1} \ and\ v_{2}$

The momentum before collision is-

$p_{i} =m_{1} v_{1} +m_{2} v_{2}$

[Here p stand for momentum.]

We are asked to calculate the final momentum of the system after collision.

The answer of the question is based law of conservation of linear momentum.

As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

Let after the collision the velocity of A and B are $v'_{1} \ and\ v'_{2}$

Hence the final momentum of the system is-

$p_{f} = m_{1} v'_{1} +m_{2} v'_{2}$

As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e

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Hence the option A is right.

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For this to occur, the surface incident must be smooth and without rough patterns on it.

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A train starts at rest in a station and accelerates at a constant 0.987 m/s2 for 182 seconds. Then the train decelerates at a co

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Answer:

$\displaystyle X_T=66.6\ km$

Explanation:

<u>Accelerated Motion </u>

When a body changes its speed at a constant rate, i.e. same changes take same times, then it has a constant acceleration. The acceleration can be positive or negative. In the first case, the speed increases, and in the second time, the speed lowers until it eventually stops. The equation for the speed vf at any time t is given by

$\displaystyle V_f=V_o+a\ t$

where a is the acceleration, and vo is the initial speed .

The train has two different types of motion. It first starts from rest and has a constant acceleration of $0.987 m/s^2$ for 182 seconds. Then it brakes with a constant acceleration of $-0.321 m/s^2$ until it comes to a stop. We need to find the total distance traveled.

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$\displaystyle t=\frac{v_f-v_o}{a}=\frac{0-179.6}{-0.321}$

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