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elena-s [515]
3 years ago
15

Two for are at an angle at 120 ,the bigger forces is 40N and the resultant is perpendicular to the smaller one. find the smaller

force ​
Physics
1 answer:
Nadya [2.5K]3 years ago
3 0

Answer:

smaller force is 20

Explanation:

Let, magnitude of the smaller force be F Newton.

Now, the resultant force makes an angle 90° with the smaller force. So, angle between resultant force and the larger force = (120° - 90°) = 30°.

So, tan 30° = (F * sin 120°) / (40 + F * cos 120°)

(1 / √3) = {F * (√3) / 2} / {40 + F * (- 1 / 2)}

80 - F = 3F

4F = 80

F = 20.

So, magnitude of smaller force is 20 Newtons.

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The binding energies of K-shell and L-shell electrons in a certain metal are EK and EL, respectively, If a Kαx ray from this met
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Answer:

The separation distance between the parallel planes of an atom is hc/2sinθ(EK - EL)

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The relationship between energy and wavelength is expressed below:

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A 4.00 m long, massless beam rests horizontally on a support 3.00 m from the left
Rus_ich [418]

If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Given the data in the question;

  • Length of the massless beam;L = 4.00m
  • Distance of support from the left end; x = 3.00m
  • First mass; m1 = 31.3 kg
  • Distance of beam from  the left end( m₁ is attached to ); x_1 = ?
  • Second mass; m_2 = 61.7 kg
  • Distance of beam from  the right of the support( m₂ is attached to ); x_1 = 0.273m

Now, since it is mentioned that the beam is in static equilibrium, the Net Torque on it about the support must be zero.

Hence, m_1g( x-x_1) = m_2gx_2

we divide both sides by g

m_1( x-x_1) = m_2x_2

Next, we make x_1, the subject of the formula

x_1 = x - [ \frac{m_2x_2}{m_1} ]

We substitute in our given values

x_1 = 3.00m - [ \frac{61.7kg\ * \ 0.273m}{31.3kg} ]

x_1 = 3.00m - 0.538m

x_1 = 2.46m

Therefore, If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Learn more; brainly.com/question/3882839

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