Question

The concentration of carbon monoxide in an urban apartment is 48μg/m3. What mass of carbon monoxide in grams is present in a room measuring 10.6ft×14.8ft×20.5ft?

Answer 1

Answer;

= 5.45 × 10-3 g or 5.45 mg

Explanation;

1 meter = 3.048 feet

Volume = 10.6 × 14.8 × 20.5 ft³  × (1/3.048 ft/m³)

             = 113.57 m³

Therefore; the mass of carbon monoxide;

                = 113.57 m³ × 48 × 10^-6 g/m³

                = 5.45 × 10^-3 g

                = 5.45 mg