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Sedaia [141]
3 years ago
5

The concentration of carbon monoxide in an urban apartment is 48μg/m3. What mass of carbon monoxide in grams is present in a roo

m measuring 10.6ft×14.8ft×20.5ft?
Physics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

Answer;

= 5.45 × 10-3 g or 5.45 mg

Explanation;

1 meter = 3.048 feet

Volume = 10.6 × 14.8 × 20.5 ft³  × (1/3.048 ft/m³)

             = 113.57 m³

Therefore; the mass of carbon monoxide;

                = 113.57 m³ × 48 × 10^-6 g/m³

                = 5.45 × 10^-3 g

                = 5.45 mg


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adell [148]

Answer:

P =18760.5 Pa

Explanation:

Given that

Volume ,V= 0.0434 m³

Mass ,m= 4.19 g = 0.00419 kg

T= 417 K

If we assume that water vapor is behaving like a ideal gas ,then we can use ideal gas equation

Ideal gas equation    P V = m R T

p=Pressure ,V = Volume ,m =mass

T=Temperature ,R=Universal gas constant

Now by putting the values

P V = m R T

For water R= 0.466 KJ/kgK

P x 0.0434 = 0.00419 x 0.466 x 417

P =18.7605 KPa

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3 years ago
A 72 kg skydiver is descending on a parachute. His speed is still increasing at 1.2 m/s2. What are the magnitude and direction o
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Answer:

Parachute exerts a force of 619.2 N upward

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As the gravitational acceleration g = 9.8 m/s2, the parachute help reduces the net acceleration to 1.2m/s. So it must exerted an upward acceleration on the skydiver of

9.8 - 1.2 = 8.6 m/s2

Since the skydiver mass is 72 kg, we can use Newton's 2nd law to calculate the force that causes this acceleration of 8.6

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5 0
3 years ago
Which of the following is true about the mass of an object?
Butoxors [25]
I believe it is the first one
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2. A car is moving with a constant speed of 10m/s. What is the total distance the car travels
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Answer:

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Find the net work W done on the particle by the external forces during the motion of the particle in terms of the initial and fi
steposvetlana [31]

Answer:

W=K_f-K_i

Explanation:

The work done on a particle by external forces is defined as:

W=\int\limits^{r_f}_{r_i} {F\cdot dr} \,

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W=\int\limits^{r_f}_{r_i}{ma\cdot dr} \,\\

Acceleration is defined as the derivative of the speed with respect to time:

W=m\int\limits^{r_f}_{r_i}{\frac{dv}{dt}\cdot dr} \,\\\\W=m\int\limits^{r_f}_{r_i}{dv \cdot \frac{dr}{dt}} \,

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W=m\int\limits^{v_f}_{v_i} v \cdot dv \,

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3 years ago
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