The molar mass is calculated by looking up the relative atomic mass values on a periodic table. The relative atomic mass is a value without units that is calculated on a Carbon-12 scale.
By looking at the periodic table (values will be to 3 significant figures [<em>2</em><em> for hydrogen though]</em>):
Molar mass (M) of 1 mole of Carbon = 12.0 g/mol
Molar mass (M) of 1 mole of Hydrogen = 1.0 g/mol
Molar mass (M) of 1 mole of Oxygen = 16.0 g/mol
So the molar mass is essentially the relative atomic mass (RAM), but molar mass has a unit, but RAM doesn't (it is a ratio).
Given the formula is C6H12O6 (without putting the numbers as subscripts), we can calculate as follows:
M (C6H12O6) = (6 x 12.0) + (12 x 1.0) + (6 x 16.0)
= 72.0 + 12.0 + 96.0
= 180.0 g/mol
Hope it's right :D
Answer:
Here you go.
Explanation:
First of all, there are reactants and products…
Reactants are in the left side (in bold).
Products are on the right (without bold)
Example; NH3 + O2 → N2 + H2O
The combustion reaction of propane would be expressed as:
C3H8 + 5O2 = 3CO2 + 4H2O
To determine the mass of water that is produced from the given amount of propane, we use the mass of propane and the relation of the substances from the balanced reaction. We do as follows:
moles propane = 22 g C3H8 ( 1 mol / 44.1 g ) = 0.50 mol C3H8
moles H2O = 0.50 mol C3H8 ( 4 mol H2O / 1 mol C3H8) = 2 mol H2O
mass H2O = 2 mol H2O ( 18.02 g / 1 mol ) = 36.04 g H2O
Therefore, the mass of water that is produced from 22 grams of propane would be 36.04 g.
Answer:
The relevant equation is:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
Explanation:
1 mol of calcium carbonate can react to 2 moles of Hydrochloric acid to produce 1 mol of water, 1 mol of calcium chloride and 1 mol of carbon dioxide.
The formed CO₂ is the reason why you noticed bubbles as the reaction took place
60.7 ml is the volume of a sample of CO2 at STP that has a volume of 75.0mL at 30.0°C and 91kPa.
Explanation:
Data given:
V1 = 75 ml
T1 = 30 Degrees or 273.15 + 30 = 303.15 K
P1 = 91 KPa
V2 =?
P2 = 1 atm or 101.3 KPa
T2 = 273.15 K
At STP the pressure is 1 atm and the temperature is 273.15 K
applying Gas Law:
= 
putting the values in the equation of Gas Law:
V2 = 
V2 = 
V2 = 60.7 ml
at STP the volume of carbon dioxide gas is 60.7 ml.
