Describe two situations in which you observed or performed an energy transformation. For each situation, name the starting form
1 answer:
You might be interested in
Answer:
a). P = 688 atm
b). P = 1083.04 atm
c).Δ G = 16.188 J/mol
Explanation:
a). Fugacity 'f' can be calculated from the following equations :
where, P = pressure , Z = compressibility
Now, the virial equation is :
........(1)
Also, PV=ZRT for real gases .......(2)
∴
So from the fugacity equation ,
Putting the value of P = 500 atm in the above equation, we get,
f = 688 atm
b). Given f = 2P
∴ P = 1083.04 atm
c). dG = Vdp -S dt at constant temperature, dT = 0
Therefore, dG = V dp
Δ G = 16.188 J/mol