Answer:
2Na(s) + 2HCl(aq) —> 2NaCl(aq) + H2(g)
Explanation:
Na(s) + HCl(aq) —> NaCl(aq) + H2(g)
Writing an ionic equation will actually help us to understand the equation and also to balance it. This is illustrated below:
Na + H+Cl-
Na is higher than H in the activity series and as such, it will displaces H from the solution and form NaCl with H2 liberated as shown below
Na + H+Cl- —> Na+Cl- + H2
Now, put 2 in front of Na, H+Cl- and Na+Cl- to balance the equation as shown below:
2Na + 2H+Cl- —> 2Na+Cl- + H2
Now we can write the elemental equation as follow:
2Na(s) + 2HCl(aq) —> 2NaCl(aq) + H2(g)
C. The neutron number.
An element is determined based on how many protons has, if the protons number change then you got a new element.
If the number of neuron change you got the same element except it will be a bit heavier or lighter if you are gaining or loosing neutrons. Those variations of an element are called the isotops of the element.
The protons and neutrons toghether form the nucleus of the atom that is heavy and dense as an elephant.
The electrons are light as fleas and stay on the shels of around the nucleus and if they are more then the number of protons they make the atom negatively charged and vice versa.
Answer:
E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g)
Explanation:
Which ONE of the following is an oxidation–reduction reaction?
A) PbCO₃(s) + 2 HNO₃(aq) ⇒ Pb(NO₃)₂(aq) + CO₂(g) + H₂O(l). NO. All the elements keep the same oxidation numbers.
B) Na₂O(s) + H₂O(l) ⇒ 2 NaOH(aq). NO. All the elements keep the same oxidation numbers.
C) SO₃(g) + H₂O(l) ⇒ H₂SO₄(aq). NO. All the elements keep the same oxidation numbers.
D) CO₂(g) + H₂O(l) ⇒ H₂CO₃(aq). NO. All the elements keep the same oxidation numbers.
E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g). YES. <u>C is reduced</u> and <u>H is oxidized</u>.
Answer:
0.5 centimetres
Explanation:
because 1 mm is 0.1 centimetres
