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Salsk061 [2.6K]
3 years ago
5

The _____ law of thermodynamics states that energy can't be created or destroyed. Two natural sources of energy on Earth are the

_____.
First, Sun and core of Earth
Second, Sun and rock
Second, Sun and biosphere
Third, core of Earth and hydrosphere
Physics
2 answers:
JulsSmile [24]3 years ago
7 0

Answer:

the answer is The <u><em>First</em></u> law of thermodynamics states that energy can't be created or destroyed. Two natural sources of energy on Earth are the <u><em>Sun and core of Earth</em></u>.

Ugo [173]3 years ago
5 0
First, Sun and core of the Earth. The rocks have some heat because of the inner heat of the planet, and the energy created by other sources are far smaller than our molten core generates.

On the other side, if you're speaking about clean sources of energy we can take advantage from, I'd go for sun and biosphere, considering the solar and wind energy they most advanced and widespread sources we have.
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A photoelectric effect experiment finds a stopping potential of 1.93 V when light of wavelength 200 nm is used to illuminate the
GenaCL600 [577]

a) Zinc (work function: 4.3 eV)

The equation for the photoelectric effect is:

E=\phi + K (1)

where

E=\frac{hc}{\lambda} is the energy of the incident photon, with

h = Planck constant

c = speed of light

\lambda = wavelength

\phi = work function of the metal

K = maximum kinetic energy of the photoelectrons emitted

The stopping potential (V) is the potential needed to stop the photoelectrons with maximum kinetic energy: so, the corresponding electric potential energy must be equal to the maximum kinetic energy,

eV=K

So we can rewrite (1) as

E=\phi + eV

where we have:

\lambda=200 nm = 2\cdot 10^{-7} m

V = 1.93 V

e is the electron charge

First of all, let's find the energy of the incident photon:

E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2\cdot 10^{-7}m}=9.95\cdot 10^{-19} J

Converting into electronvolts,

E=\frac{9.95\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=6.22 eV

And now we can solve eq.(1) to find the work function of the metal:

\phi = E-eV=6.22 eV-1.93 eV=4.29 eV

so, the metal is most likely zinc, which has a work function of 4.3 eV.

b) The stopping potential is still 1.93 V

Explanation:

The intensity of the incident light is proportional to the number of photons hitting the surface of the metal. However, the energy of the photons depends only on their frequency, so it does not depend on the intensity of the light. This means that the term E in eq.(1) does not change.

Moreover, the work function of the metal is also constant, since it depends only on the properties of the material: so \phi is also constant in the equation. As a result, the term (eV) must also be constant, and therefore V, the stopping potential, is constant as well.

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Explanation:

given solution

h=45m v^2=u^2+2gh

g=10m/s^2 v^2=0^2+2×10m/s^2×45m

vi=0 v^2=900m^2/s^2

  • v=30
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If force remains constant and acceleration decreases what must happen to the mass
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That can only be happening if the mass mysteriously increased somehow.  I'd like to know how in the world THAT happened.

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The element in an incandescent light bulb that releases light energy is
Leviafan [203]
A thin tungsten filament
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Describe what would happen if you rubbed a mineral with a Mohs hardness value of 7 against a mineral with a value of 5?
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