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iVinArrow [24]
3 years ago
10

according to newton's law of universal gravitation, in which of the following situations does the gravitational attraction betwe

en the bodies always increases.
Physics
1 answer:
Alex17521 [72]3 years ago
4 0

Explanation:

The force acting between two masses is given by :

F=G\dfrac{m_1m_2}{d^2}........(1)

Where

G is the universal gravitational constant

m_1\ and\ m_2 are masses

d is the distance between two masses

It is clear from equation (1) that the gravitational attraction between the bodies always increases if the masses of bodies increases and when the separation between masses decreases.

So, the correct answer is "the masses increase, and the distance between the centers of mass decreases". This is because the force of gravitation is directly proportional to the masses and inversely proportional to the separation.

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The term used to describe the ability of a conduit to conduct flow is:
MissTica
The answer is , Conductance
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A lead ball is dropped into a lake from a diving board 5.0 m above the water. After entering the water, it sinks to the bottom w
nirvana33 [79]

Answer:

|D_{depth} |=19.697m

Explanation:

To find Depth D of lake we must need to find the time taken to hit the water.So we use equation of simple motion as:

Δx=vit+(1/2)at²

x_{f}-x_{i}=v_{i}t+(1/2)at^{2}\\  -5.0m=(o)t+(1/2)(-9.8m/s^{2} )t^{2}\\ -4.9t^{2}=-5.0\\ t^{2}=5/4.9\\t=\sqrt{1.02} \\t=1.01s

As we have find the time taken now we need to find the final velocity vf from below equation as

v_{f}=v_{i}+at\\v_{f}=0+(-9.8m/s^{2} )(1.01s) \\v_{f}=-9.898m/s

So the depth of lake is given by:

first we need to find total time as

t=3.0-1.01 =1.99 s

|D_{depth} |=|vt|\\|D_{depth} |=|(-9.898m/s)(1.99s)|\\|D_{depth} |=19.697m

6 0
3 years ago
100 POINTS FOR THE CORRECT ANSWER/ EXPLANATION.
GuDViN [60]

Answer:

d) 15.12 N

e) 15.12 N

Explanation:

Draw a free body diagram of the each block.

Block A has three forces on it: weight force mAg pulling down, normal force N pushing up, and tension force T pulling down.

Block B has two forces on it: weight force mBg pulling down, and tension force T pulling up.

Sum of forces on A in the y direction:

∑F = ma

T + N − mAg = mAa

N = mAa + mAg − T

N = mA (a + g) − T

Sum of forces on B in the y direction:

∑F = ma

T − mBg = mBa

T = mBa + mBg

T = mB (a + g)

Plug in values:

T = (1.80 kg) (-1.60 m/s² + 10 m/s²)

T = 15.12 N

N = (3.60 kg) (-1.60 m/s² + 10 m/s²) − 15.12 N

N = 15.12 N

So the answers to (d) and (e) are both 15.12 N.

6 0
3 years ago
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An undersea research chamber is spherical with an external diameter of 5.50 m . The mass of the chamber, when occupied, is 87600
arsen [322]

Answer:

A)

8.75\times10^{5} N

B)

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Explanation:

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V = \frac{4\pi (\frac{d}{2} )^{3}}{3}\\ V = \frac{4(3.14) (\frac{5.50}{2} )^{3}}{3}\\V = 87.07 m^{3}

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Part A)

Force of buoyancy by seawater on the chamber is given as

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Weight of the chamber is given as

F_{g} = mg \\

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T + F_{g} = F_{b}\\T + m g = F_{b}\\T + (87600) (9.8) = 8.75\times10^{5}\\T = 16520 N \\T = 1.7\times10^{4} N

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3 years ago
A boom is to be dropped from moving helicopter on the ground. Explain how can it hut the target ?
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Answer:

A bomb that is dropped from a moving helicopter doesn't fall directly downward rather it follows the parabolic path as it were thrown horizontally from a height with certain initial velocity. Therefore, the bomb should be dropped from farther distance equal to the horizontal range before the helicopter reaches above the target.

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