The answer is , Conductance
Answer:

Explanation:
To find Depth D of lake we must need to find the time taken to hit the water.So we use equation of simple motion as:
Δx=vit+(1/2)at²

As we have find the time taken now we need to find the final velocity vf from below equation as

So the depth of lake is given by:
first we need to find total time as
t=3.0-1.01 =1.99 s

Answer:
d) 15.12 N
e) 15.12 N
Explanation:
Draw a free body diagram of the each block.
Block A has three forces on it: weight force mAg pulling down, normal force N pushing up, and tension force T pulling down.
Block B has two forces on it: weight force mBg pulling down, and tension force T pulling up.
Sum of forces on A in the y direction:
∑F = ma
T + N − mAg = mAa
N = mAa + mAg − T
N = mA (a + g) − T
Sum of forces on B in the y direction:
∑F = ma
T − mBg = mBa
T = mBa + mBg
T = mB (a + g)
Plug in values:
T = (1.80 kg) (-1.60 m/s² + 10 m/s²)
T = 15.12 N
N = (3.60 kg) (-1.60 m/s² + 10 m/s²) − 15.12 N
N = 15.12 N
So the answers to (d) and (e) are both 15.12 N.
Answer:
A)

B)

Explanation:
= diameter of the spherical chamber = 5.50 m
Volume of the spherical chamber is given as

= density of the seawater = 1025 kg m⁻³
Part A)
Force of buoyancy by seawater on the chamber is given as

Part B)
= tension force in the cable in upward direction
= mass of the chamber = 87600 kg
Weight of the chamber is given as

Using equilibrium of force in the vertical direction, we have

Answer:
A bomb that is dropped from a moving helicopter doesn't fall directly downward rather it follows the parabolic path as it were thrown horizontally from a height with certain initial velocity. Therefore, the bomb should be dropped from farther distance equal to the horizontal range before the helicopter reaches above the target.