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3 years ago

PLEASE HELP ME I BEG YOU

2 answers:

7 0

1. Only if new observations led to a change in our current knowledge.

2. place their own moral views about the needs of society

3. True

4. False

5. True

6. True

7. Distillation

8. the number of electrons

9. the element becomes a different element

10. Atomic radiation will increase

11. Increases

I hope this helps!

slamgirl [31]3 years ago

5 0

1) Only if new observations led to a change in our current knowledge.

2) place their own moral views about the needs of society

3) FALSE

4) FALSE

5) FALSE(i think)

6) TRUE

7) Distillation

8) the # of neutrons

9) the element becomes a different element

10) atomic radii increase

11) decreases

i hope these are right and helps. please give me brainliest

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For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici

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Question:

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

Answer:

The mean activity coefficient for HCl solution is 0.78.

Explanation:

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

$E=E_{0}-0.0514 \mathrm{V} \ln \gamma$

As we know that $E_{0}$ = 0.22 V and E = 0.342 V, the equation will become

$0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma$

$0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)$

$0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)$

$\frac{0.12}{0.0514}=-\ln (0.124 \gamma)$

$-2.3346=\ln (0.124 \gamma)$

$e^{-2.3346}=0.124 \gamma$

$0.0968=0.124 \gamma$

$\gamma=\frac{0.0968}{0.124}=0.78$

So, the mean activity coefficient is 0.78.

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2 years ago

Two isotopes of hypothetical element X exist with abundances of 30.00% 100X and 70.00% 101X. What is the approximate atomic mass

Rasek [7]

Answer:

C. 100.7 amu

Explanation:

Isotopes of an element are atoms of an element with the same atomic number but different atomic masses. Each atomic mass of an isotope is known as an isotopic mass. An element that exhibits isotope, that is, that have two or more isotopes has a relative atomic mass that is not a whole number.

Relative atomic mass of X is the sum of the products of the relative abundances of each isotope and its isotopic mass.

For Isotope ¹⁰⁰X: 30% × 100 = 30 amu

For Isotope ¹⁰¹X: 70% × 101 = 70.7 amu

Relative atomic mass of X = (30 + 70.7) amu = 100.7 amu

Therefore, the approximate atomic mass of X is 100.7 amu

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2 years ago

The elements X and Y combine in different ratios to form four different types of compounds: XY, XY2, XY3, and XY4. Consider that

Law Incorporation [45]

Answer:

Ratios in order of increasing value ; The ratio of the mass ratio of Y to X in XY2 to the mass ratio of Y to X in XY, The ratio of the mass ratio of Y to X in XY3 to the mass ratio of Y to X in XY, The ratio of the mass ratio of Y to X in XY4 to the mass ratio of Y to X in XY

1) Mass ratio = 3

2) Mass ratio = 2

3) Mass ratio = 4

Explanation:

The detailed and step by step calculation is shown in the attachment.

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If you use 1 mole of NaOH, how much NaAl(OH)4 is produced

abruzzese [7]

Answer:
81.97 g of NaAl(OH)₄

Solution:
The reaction for the preparation of Sodium Aluminate from Aluminium Metal and NaOH is as follow,

2 NaOH + 2 Al + 6 H₂O → 2 NaAl(OH)₄ + 3 H₂

According to this equation,

2 Moles of NaOH produces = 163.94 g (2 mole) of NaAl(OH)₄
So,
1 Mole of NaOH will produce = X g of NaAl(OH)₄

Solving for X,
X = (1 mol × 163.94 g) ÷ 2 mol

X = 81.97 g of NaAl(OH)₄

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2 years ago