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aleksandrvk [35]
3 years ago
6

In the reaction, 2K (s) + 2H2O (l) produces 2KOH (aq) produces H2 (g), which of the reactants is a solid

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

k

Explanation:

2K (s) + 2H2O (l) produces 2KOH (aq) produces H2 (g),

2K (s) + 2H2O (l) --> 2KOH (aq) + H2 (g)

(s) = solid

(l) = liquid

(g) = gas

Left hand side are reactants

2K (s) + 2H2O (l)

Right hand side are products

2KOH (aq) + H2 (g)

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Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2NH3(g) 3N2O(g)4N2(g) 3H2O
trasher [3.6K]

Answer: \Delta H^{0} = -879.15 kJ/mol

Explanation: <u>Heats</u> <u>of</u> <u>formation</u> is the amount of heat necessary to create 1 mol of a compound from its molecular constituents. The basic conditions the substance is formed is at standard conditions: 1 atm and 25°C. Each compound has its own heat of formation per mol of compound (kJ/mol), but to an element is assigned a value of zero.

<u>Standard</u> <u>Enthalpy</u> <u>Change</u> is defined as the heat absorbed or released when a reaction takes place. It can be positive or negative, which means reaction is endothermic or exothermic, respectively.

Enthalpy change is calculated as the difference between the sum of heat formation of products and the sum of heat formation of the reactants:

\Delta H^{0}=\Sigma H^{0}_{f}_{(products)}-\Sigma H^{0}_{f}_{(reactants)}

For the reaction

   2NH₃   +      3N₂O   →      4N₂    +     3H₂O

2(-46.2)   +     3(82.05)      4(0)    +    3(-241.8)

\Delta H^{0}=3(-241.8)-[ 2(-46.2)+3(82.05)]

\Delta H^{0}=-725.4-153.75

\Delta H^{0}=-879.15

<u>The standard enthalpy change for the reaction is </u>\Delta H^{0}=-879.15<u> kJ</u>

8 0
3 years ago
What determines crystal size in minerals formed by lava or magma?
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When magma cools, crystals form because the solution is super-saturated with respect to some minerals. If the magma cools quickly, the crystals do not have much time to form, so they are very small. If the magma cools slowly, then the crystals have enough time to grow and become large.

Explanation:

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Explanation:

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3 years ago
The molar absorptivity of a tyrosine residue at 280 nm is 2000 M-1cm-1, while for tryptophan it is 5500 M-1cm-1. A protein has b
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Answer:

There are 4 tryptophans in the protein.

Explanation:

According to question,  protein contains one tyrosine residue and say x number of tryptophans.

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Molar absorptivity of a protein solution : \epsilon

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Absorbance of protein solution at 280 nm = A = 0.024

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0.024=(1\times 2000 M^{-1}cm^{-1}+x\times 5500 M^{-1}cm^{-1})\times 1 cm\times 1.0\times 10^{-6} M

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Explanation:

7 0
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