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aleksandrvk [35]
3 years ago
6

In the reaction, 2K (s) + 2H2O (l) produces 2KOH (aq) produces H2 (g), which of the reactants is a solid

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

k

Explanation:

2K (s) + 2H2O (l) produces 2KOH (aq) produces H2 (g),

2K (s) + 2H2O (l) --> 2KOH (aq) + H2 (g)

(s) = solid

(l) = liquid

(g) = gas

Left hand side are reactants

2K (s) + 2H2O (l)

Right hand side are products

2KOH (aq) + H2 (g)

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Simora [160]

Heat required to raise the temperature = 159.505 J

<h3>Further explanation</h3>

Given

c = specific heat of Beryllium = 1.825 J/g C

m = mass = 2.3 g

Δt = Temperature difference : 60 - 22 = 38 °C

Required

Heat required

Solution

Heat can be formulated

Q = m.c.Δt

Input the value :

Q = 2.3 x 1.825 x 38

Q = 159.505 J

8 0
2 years ago
What is the answer?
rosijanka [135]
A generator because they connect each other in physical attraction
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3 years ago
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Elimination of the pharmaceutical IV antibiotic gentamicin follows first-order kinetics. If the half-life of gentamicin is 1.5 h
Genrish500 [490]

Explanation:

The given data is:

The half-life of gentamicin is 1.5 hrs.

The reaction follows first-order kinetics.

The initial concentration of the reactants is 8.4 x 10-5 M.

The concentration of reactant after 8 hrs can be calculated as shown below:

The formula of the half-life of the first-order reaction is:

k=\frac{0.693}{t_1_/_2}

Where k = rate constant

t1/2=half-life

So, the rate constant k value is:

k=\frac{0.693}{1.5 hrs}

The expression for the rate constant is :

k=\frac{2.303}{t} log \frac{initial concentration}{concentration after time "t"}

Substitute the given values and the k value in this formula to get the concentration of the reactant after time 8 hrs is shown below:

\frac{0.693}{1.5 hrs} =\frac{2.303}{8 hrs} x log \frac{8.4x10^-^5}{y} \\ log \frac{8.4x10^-^5}{y} =1.604\\\frac{8.4x10^-^5}{y}=10^1^.^6^0^4\\\frac{8.4x10^-^5}{y}=40.18\\y=\frac{8.4x10^-^5}{40.18} \\=>y=2.09x10^-^6

Answer: The concentration of reactant remains after 8 hours is 2.09x10^-6M.

5 0
3 years ago
Calculate the number of miles of magnesium,chlorine, and oxygen atoms in 5.00 moles of magnesium perchlorate
Zigmanuir [339]

Answer:

5.00 mol Mg

10.0 mol Cl

40.0 mol O

Explanation:

Step 1: Given data

Moles of Mg(ClO₄)₂: 5.00 mol

Step 2: Calculate the number of moles of Mg

The molar ratio of Mg(ClO₄)₂ to Mg is 1:1.

5.00 mol Mg(ClO₄)₂ × 1 mol Mg/1 mol Mg(ClO₄)₂ = 5.00 mol Mg

Step 3: Calculate the number of moles of Cl

The molar ratio of Mg(ClO₄)₂ to Cl is 1:2.

5.00 mol Mg(ClO₄)₂ × 2 mol Cl/1 mol Mg(ClO₄)₂ = 10.0 mol Cl

Step 4: Calculate the number of moles of O

The molar ratio of Mg(ClO₄)₂ to Cl is 1:8.

5.00 mol Mg(ClO₄)₂ × 8 mol O/1 mol Mg(ClO₄)₂ = 40.0 mol O

4 0
3 years ago
Best way to separate a solid from a liquid what separation technique is needed​
allsm [11]
Filtration is a method for separating an insoluble solid from a liquid.
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