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k0ka [10]
3 years ago
12

Hi my friends here I am to say that in exam I got 1st rank so thanks effort of your my friends

Chemistry
2 answers:
Rina8888 [55]3 years ago
6 0

Answer:

yay glad you passed your exam even tho i have no memory of knowing you :D

Explanation:

Nitella [24]3 years ago
3 0

Answer:

ooh great

congratulations

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How many grams of silver nitrate are needed to react with 156.2g of sodium sulfide to produce 595.8g of silver sulfide and 340.0
qaws [65]
Before proceeding, we should write the reaction equation to better understand what is happening:
2AgNO₃ + Na₂S → Ag₂S + 2NaNO₃

Now, we may apply the law of conservation of mass, due to which the total mass before a chemical reaction is equivalent to the total mass after a chemical reaction. Therefore:
Mass of silver nitrate + mass of sodium sulfide = mass of silver sulfide + mass of sodium nitrate

Mass of silver nitrate + 156.2 = 595.8 + 340
Mass of silver nitrate = 779.6 grams
3 0
3 years ago
Is chemistry hard in grade 11<br>explain to me everything plsss thanks ​
damaskus [11]

Answer: yes it’s hard

Explanation:

8 0
2 years ago
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Calculate in gramm the mass of 0.1 mole of hydrochloric acid(h=1 ,cl=35.5)​
babunello [35]

Answer:

mass of HCl = 3.65 g

Explanation:

Data Given:

Moles of hydrochloric acid HCl = 0.1 mole

Mass in grams of hydrochloric acid HCl = ?

Solution:

Mole Formula

                  no. of moles = Mass in grams / molar mass

To find Mass in grams rearrange the above Formula

                Mass in grams = no. of moles x molar mass . . . . . . . (1)

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

Put values in equation 1

              Mass in grams = 0.1 mole x 36.5 g/mol

              Mass in grams = 3.65 g

mass of HCl = 3.65 g

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3 years ago
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