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ollegr [7]
3 years ago
11

A spider is crawling on a wall. First it crawls 1 meter up, then 1 meter to the left, and then 1 meter down. what is its total d

isplacement

Physics
2 answers:
maria [59]3 years ago
4 0
1 meter up, 1 meter to the left and then 1 metter down.
It goes 1 meter up and 1 meter down, so its in the same place. The only displacement is 1 meter to the left.

Look at picture:

(hope this helps)

alexandr1967 [171]3 years ago
3 0
1 meter up and then 1 meter left, and then 1 meter down. The total displacement would be 1 meter. See Ayah's pic to help you understand more better:)<span />
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A 20kg block is sliding down a 30° ramp at a constant velocity. Calculate the normal force acting on the block. Calculate the co
tatiyna

Let me try:

Normal force= 169.74N

Coefficient of kinetic friction= 0.577

Explanation

a. For a given inclined plane, normal friction is equal to the force perpendicular to the plane which is equal to

mgcos theta = 20×9.8× cos30 = 169.74N

b. The coefficient of kinetic friction for an inclined plane is given as

tan theta =tan 30 = 0.577

8 0
3 years ago
The movie "The Gods Must Be Crazy" begins with a pilot dropping a bottle out of an airplane. A surprised native below, who think
Sergio039 [100]

Answer:

⇔⇔⇔↑∑∑∩∅¬⊕║⊇↔∴∉∵

Explanation:

8 0
3 years ago
Lava is rock that has undergone a physical change and has liquefied. What is known about this change?
RideAnS [48]
It was super heated to turn in to a liquid
3 0
3 years ago
The cue ball is deflected so that it makes an angle of 30.0° with its original direction of travel.
Alexus [3.1K]

Answer:

(a) θ= 43.89°

(b) v_{1} = 1.88\sqrt{3} \frac{m}{s}

    v_{2} = 6.79 \frac{m}{s}

Explanation:

Ball 1:

u_{1} = 7.52\frac{m}{s}

Ball 2:

u_{2} = 0\frac{m}{s}

As the collision is elastic, it means that kinetic energy and momentum are conserved. Following that, we apply the law of conservation of energy and momentum:

\frac{1}{2} m_{1}u_{1}^{2}   = \frac{1}{2} m_{1}v_{1}^{2} + \frac{1}{2} m_{2}v_{2}^{2}

and

m_{1}u_{1} =   m_{1}v_{1} + m_{2}v_{2}

Where u is the velocity before the collision, and v are the velocities after the collision. Both previous equations can be simplified as:

u_{1}^{2}   = v_{1}^{2} + v_{2}^{2}

and

u_{1} =   v_{1} + v_{2}

This because the two balls have the same mass. We know that the cue ball is deflected and makes an angle of 30°. From conservation in x-direction, we get::

56.55 = v_{1} ^{2} + v_{2} ^{2}

and

u_{1} = v_{1}cos(30) +  v_{2}cos(\theta)

Solving we get:

(\frac{2u_{1}-\sqrt{3}v_{1}  }{2cos(\theta)})^{2}  = 56.55-v_{1} ^{2}

From conservation in y-direction, we get:

0 = v_{1}sin(30) -  v_{2}sin(\theta)

From this, we solve this equation system and get the answers. Remember to add 30° to the angle obtained.

8 0
3 years ago
What kind of energy does a light bolt have ?
adell [148]
It has thermal energy
7 0
3 years ago
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