Explanation:
The given data is as follows.
= 57 kg, 
= 79 kg
= 6.5 m, 
= (6.5 - 1.9) m = 4.6 m
(a) The sum of torque ends about far end is as follows.
= 0
= 0
T = 828 N
Therefore, 828 N is the tension in the cable closer to the painter.
(b) Now, we will calculate the sum about close ends as follows.
= 0
T= 506 N
Therefore, 506 N is the tension in the cable further from the painter.
Weight of the child m = 50 kg
Radius of the merry -go-around r = 1.50 m
Angular speed w = 3.00 rad/s
(a)Child's centripetal acceleration will be a = w^2 x r = 3^2 x 1.50 => a = 9 x
1.5
Centripetal Acceleration a = 13.5m/sec^2
(b)The minimum force between her feet and the floor in circular path
Circular Path length C = 2 x 3.14 x 1.50 => c = 3 x 3.14 => C = 9.424
Time taken t = 2 x 3.14 / w => t = 6.28 / 3 => t = 2.09
Calculating velocity v = distance / time = 9.424 / 2.09 m/s => v = 4.5 m/s
Calculating force, from equation F x r = mv^2 => F = mv^2 / r => 50 x (4.5)^2
/ 1.5
F = 50 x 3 x 4.5 => F = 150 x 4.5 => F = 675 N
(c)Minimum coefficient of static friction u
F = u x m x g => u = F / m x g => u = 675/ 50 x 9.81 => 1.376
u = 1.376
Hence with the force and the friction coefficient she is likely to stay on merry-go-around.
Explanation:
actually, the question would need to give you what is the gravitational force, so let's take the average of the gravitational for me which is 10 N /kg
and the formula for finding weight is
W = mg
W = (5)(10)
W = 50 N
hope it is helpful, if not please report it so that someone else gets to try
please vote
The answer is A and E.
Hope this helps! :D
