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sertanlavr [38]

3 years ago

14

The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions? Which of the following

equations is used in the process of solving this problem?
x2 - 7x + 70 = 0
x2 - 7x + 10 = 0
x2 + 7x - 10 = 0

1 answer:

Verizon [17]3 years ago

5 0

Let the number be x.
x^2=7x-10
x^2-7x+10=0

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