The radiation emitted is a beta particle with a -1 charge. <span>Beta particles have a </span><span>medium penetrating power. An emission of beta particles requires shielding because of the hazards it pose to humans. Thus, one characteristic of this radiation is that some shielding is required.</span>
Answer:
oxygen is reduced to form water.
Explanation:
Cellular respiration
It is the set of reactions in which the ac. Pyruvic produced by glycolysis is split into CO2 and H2O and 36 ATP are produced. In eukaryotic cells breathing is performed in the mitochondria. It occurs in two stages:
- PIRUVATE OXIDATION
- AC CYCLE TRICARBOXYL
The "problem" with fermentation is that, by using organic molecules as terminal electron acceptors and having to dispose of the resulting product (lactic acid / ethanol) as waste, the potential energy of these compounds is lost.
The alternative solution is to use some non-organic molecule that can accept electrons and thus become a reduced molecule. Oxygen is perfect for this, because after receiving the electrons it combines with two protons, thus becoming the perfect liquid residue for the environment: H2O.
Answer:
The main purpose for converting numbers into scientific notation is to make calculations with surpisingly large or small numbers less complicated. Since zeros are not used to place the decimal point, all of the digits in a number in scientific notation are meaningful and easier to read. Hope this helps!
Explanation:
Answer:
3.94 L
Explanation:
From the question given above, the following data were obtained:
Mass of O₂ = 5.62 g
Volume of O₂ =?
Next, we shall determine the number of mole present in 5.62 g of O₂. This can be obtained as follow:
Mass of O₂ = 5.62 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mole of O₂ =?
Mole = mass / molar mass
Mole of O₂ = 5.62 / 32
Mole of O₂ = 0.176 mole
Finally, we shall determine the volume of 5.62 g (i.e 0.176 mole) of O₂ at STP. This can be obtained as follow:
1 mole of O₂ occupied 22.4 L at STP.
Therefore, 0.176 mole of O₂ will occupy = 0.176 × 22.4 = 3.94 L at STP.
Thus 5.62 g (i.e 0.176 mole) of O₂ occupied 3.94 L at STP
