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andrezito [222]
3 years ago
9

Which is higher the freezing point of water or the melting point of ice?

Chemistry
2 answers:
MrRissso [65]3 years ago
8 0
Pretty sure they're the same.
hoa [83]3 years ago
7 0
Melting point of ice
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There is a 50 g sample of ra-229. It has a half-life of 4 minutes.how much will be left after 12 minutes? a. 3.13 g b. 6.25 g c.
polet [3.4K]

It's B. 6.25

first divide 50/2

then divide 25/2

after that divide 12.5/2

Then you get 6.25

Hope it helps!

3 0
3 years ago
a can of diet soda will float in water while a can of regular sugar soda will sink. which of these best describes why this would
Yuri [45]
I think the correct answer from the choices listed above is option A. A can of diet soda will float in water while a can of regular sugar soda will sink. This is due to the reason that the regular soda is more dense than the diet soda. Hope this answers the question.
5 0
3 years ago
How can i find the number of neutrons in an element ​
lawyer [7]

Answer:

The mass number is the sum of protons and neutrons. This means to find the number of neutrons you subtract the number of protons from the mass number. On the periodic table, the atomic number is the number of protons, and the atomic mass is the mass number.

Explanation:

7 0
3 years ago
Read 2 more answers
Consider the following reaction: NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2 How many mol of CO2 would be produced from the complete
Assoli18 [71]

Answer:

0.208mole of CO2

Explanation:

First, let us calculate the number of mole of HC3H3O2 present.

Molarity of HC3H3O2 = 0.833 mol/L

Volume = 25 mL = 25/100 = 0.25L

Mole =?

Mole = Molarity x Volume

Mole = 0.833 x 0.25

Mole of HC3H3O2 = 0.208mole

Now, we can easily find the number of mole of CO2 produce by doing the following:

NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2

From the equation,

1mole of HC2H3O2 produced 1 mole of CO2.

Therefore, 0.208mole of HC2H3O2 will also produce 0.208mole of CO2

6 0
3 years ago
Read 2 more answers
How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?
Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

pH= -log[H]\\pH= -log (\frac{kw}{[OH]})

8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}

[OH]=1.69E-6

This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:

Cu(OH)_2 -> Cu^{2+} + 2OH^-

In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

The expression for Kps is:

Kps= [Cu^{2+}] [OH]^2

The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

Kps= s*(2s+1.69E-6)^2

"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is s=4.96E-8 mol/L

Now, let us calculate the moles in 1 L:

moles Cu(OH)_2 = 4.96E-8 mol/L * 1 L = 4.96E-8 moles

7 0
3 years ago
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