Molar mass of LiBr (mm )= 86.845 g/mol
Molarity ( M ) = 4 M
Mass of solute ( m ) = 100 g
Volume ( V ) = in liters ?
V = m / mm * M
V = 100 / 86.845 * 4
V = 100 / 347.38
V = 0.2875 L
hope this helps!.
If you change the subscripts it would change the reactants or products and then you would be solving a different formula, you would change what the chemical is
About 2 gallons. (I got 1.92592592593)
