Answer:
NO is the limiting reactant.
Explanation:
4NH3 + 6NO --> 5N2 + 6H2O
Molar ration NH3 : NO = 10: 30 = 1: 3
Stoichiometric molar ration NH3:NO = 4:6 = 2:3
NO is the limiting reactant.
 
        
             
        
        
        
14 electrons because there are 7 orbitals (2x7=14)
        
             
        
        
        
Answer: 15.1 grams
Given reaction:
Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3
Mass of Na2CO3 = 20.0 g
Molar mass of Na2CO3 = 105.985 g/mol
# moles of Na2CO3 = 20/105.985 = 0.1887 moles
Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH
# moles of NaOH produced = 0.1887*2 = 0.3774 moles
Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol
Mass of NaOH produced = 0.3774*39.996 = 15.09 grams
Explanation:
 
        
                    
             
        
        
        
Explanation:
Transfer of mass A into stagnant film B depends on the availability of driving force.
Whereas driving force is the pressure difference at the surface of A and the bulk.
As,       
            
Therefore, putting the given values into the above formula as follows.
          
                      = 
                      = 0.132 
Thus, we can conclude that the flux of A from a surface into a mixture of A and B is 0.132 
 
        
             
        
        
        
Answer:
lead ii nitrate is the answer