Answer:
-800 kJ/mol
Explanation:
To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).
First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:
Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol
moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄
Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:
ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol
Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).
Answer:
In one mole of glucose, there are
6.022×1023
individual glucose molecules
Explanation:
Answer:
.✓is related to the solute content
✓gives information about potential changes in cell volume when cells are placed in that solution
√is related to membrane permeability to solutes.
Explanation:
Tonicity of a solution can be explained as how an extracellular solution can give room for the liquid to move in and out of the cell through osmosis.
It should be noted that Tonicity of a solution is
.✓is related to the solute content
✓gives information about potential
changes in cell volume when cells are placed in that solution
√is related to membrane permeability to solutes.
Answer:
Explanation:
No, I don't owe nothing
Stop acting funny
5I've seen them running
Coming for more
4646
Answer:
Breaker A
Explanation:
Because the temperature is cooler in A then the rest
