Common thing is that their outmost shell is completely filled with the electrons. They are inert gases.
Answer:
Zero-Nine
Explanation:
this is becasue these numbers are rather small and if you plug these numbers into an equation you will most likely get 0.
The % error in the second trial is calculated as follows
% error = actual molarity/ theoretical molarity x100
= 0.83/0.95 x100 = 87.4% error of second trial
Answer:
Adult tickets = A (cost $8)
student tickets = S (cost $4)
8(80) + 4(60) = 880
Explanation:
Substitution.
Adult tickets = A (cost $8)
student tickets = S (cost $4)
The drama class sold 20 more adult tickets than student tickets:
A = S + 20 (equation 1)
The class collected $880 from tickets:
8A + 4S = 880 (equation 2)
How many adult tickets were sold?
A = S + 20
8A + 4S = 880
we substitute the first equation into the second:
8(S+20) + 4S = 880
8S + 160 + 4S = 880
12S = 720
S = 60
Next we find the adult tickets by substituting back:
A = S + 20
A = 60 + 20
A = 80
Check our answer by substituting our answers in equation 2:
8A + 4S = 880 (equation 2)
8(80) + 4(60) = 880
640 + 240 = 880
880 = 880
If the reaction started with 32g of Sulfur and 56 grams of Iron, then mass of produced FeS is 88 grams.
<h3>What is the relation between mass & moles?</h3>
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
- W = given mass
- M = molar mass
Moles of Fe = 56g / 56g/mol = 1 mol
Moles of S = 32g / 32g/mol = 1 mol
Given chemical reaction is:
Fe + S → FeS
From the stoichiometry of the reaction same moles of iron and sulfur are required to produce equal moles of iron sulfide. Means 1 mole of iron produces 1 moles of iron sulfide and mass of iron sulfide will be calculated as:
W = (1mol)(88g/mol) = 88g
Hence required mass of iron sulfide is 88 grams.
To know more about mass & moles, visit the below link:
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