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Ivahew [28]
4 years ago
10

For what purpose is a screen name used?

Physics
2 answers:
navik [9.2K]4 years ago
6 0
A unique sequence of characters that a person chooses to use for identification purposes when interacting with others online, as in computer games, instant messaging, or forums.   <span />
Alchen [17]4 years ago
5 0
Screen name is the name a user chooses to use when communicating with others online.
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What is the role of neutrons in the nucleus. ​
Serjik [45]

Answer:

<em><u>To be neutral</u></em>

Explanation:

Neutrons are electrically neutral but contribute to the mass of a nucleus to nearly the same extent as the protons. Neutrons can explain the phenomenon of isotopes (same atomic number with different atomic mass). The main role of neutrons is to reduce electrostatic repulsion inside the nucleus.

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Do we have free will or is everything predestined?
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Predestination, in theology, is the doctrine that all events have been willed by God, usually with reference to the eventual fate of the individual soul. Explanations of predestination often seek to address the "paradox of free will", whereby God's omniscience seems incompatible with human free will.
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How can water boil without heat?​
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3 0
3 years ago
Ok so if atoms cant touch then why can the average human experience touch
djyliett [7]
While we think and feel that we are touching, we actually are not(: It’s all an illusion made by the brain
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3 years ago
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A size-5 soccer ball of diameter 22.6 cm and mass 426 g rolls up a hill without slipping, reaching a maximum height of 5.00 m ab
Drupady [299]

Answer

According the conservation of energy

\dfrac{1}{2}mv_i^2+\dfrac{1}{2}I\omega_i^2+0 = mgh + 0

I for ball = \dfrac{2}{3}mr^2

\dfrac{1}{2}mv_i^2+\dfrac{1}{2} \dfrac{2}{3}mr^2\omega_i^2= mgh

\omega_i = \dfrac{v_i}{r}

v_i^2+\dfrac{2}{3}r^2(\dfrac{v_i}{r})^2 = 2gh

v_i^2+\dfrac{2}{3}v_i^2 = 2gh

v_i^2+[1+\dfrac{2}{3}]=2gh

v_i^2\dfrac{5}{3}=2gh

v_i=\sqrt{\dfrac{6gh}{5}}=\sqrt{\dfrac{6\times 9.8\times 5}{5}}

v_i = 7.67\ m/s

a) \omega_i = \dfrac{v_i}{R}

\omega_i = \dfrac{7.67}{0.113}

\omega_i =67.87\ rad/s

b) K_{rot} = \dfrac{1}{2}\dfrac{2}{3}mR^2\omega_i^2

   K_{rot} = \dfrac{1}{3}\times 0.426\times 0.112^2\times 67.87^2

   K_{rot} = 8.205\ J

4 0
3 years ago
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