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elena55 [62]
3 years ago
5

Robebobeccoba fires a bullet from a gun while aiming at a target 149 m away. If the

Physics
1 answer:
Snezhnost [94]3 years ago
5 0

Answer:

329.6 m/s

Explanation:

The bullet has a projectile motion, consisting of two separate motions:

- A horizontal motion with constant velocity

- A free fall motion (constant acceleration) in the vertical direction

The bullet misses the target vertically by 1 m: this means that 1 m is the vertical dispalcement of the bullet. So we can find the total time of the flight by using the suvat equation

s=ut+\frac{1}{2}at^2

where

s = 1 m is the vertical displacement

u = 0 is the initial vertical velocity

a=g=9.8 m/s^2 is the acceleration due to gravity

t is the time

Solving for t,

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(1)}{9.8}}=0.452 s

The horizontal motion is at constant speed, which is given by

v_x = \frac{d}{t}

where

d = 149 m is the distance covered by the bullet

t = 0.452 s is the time taken

Substituting,

v_x = \frac{149}{0.452}=329.6 m/s

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Answer:

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Solving for v, we get:

v = \frac{m_1 u_1+m_2 u_2}{m_1+m_2}=\frac{(91.5)(2.73)+(63.5)(3.09)}{91.5+63.5}=2.88\ m/s

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