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3 years ago

6

The process by which the seafloor moves apart at mid-ocean ridges is called _____.

2 answers:

worty [1.4K]3 years ago

6 0

I think the answer would be C, because to me that's one that makes sense, I hope that I could help, Have a great Thursday!

Ira Lisetskai [31]3 years ago

5 0

Answer:

C. Sea floor spreading.

Explanation:

The geological process by which the tectonic plates separate from each other in the seabed allowing the rise of magma is known as sea floor spreading.

In this process, magma comes into contact with cold water and solidifies rapidly, generating a ridge at the bottom of the ocean, as is shown in the image.

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What electrical force dies a Uranium nucleus exert on one of its inner electrons, located at a distance of 175 picometers (= 1.7

AlekseyPX

Answer:

correct option is d) 7.0 x 10^-7 N

Explanation:

given data

distance = 175 picometers = 1.75 × $10^{-10}$ m

to find out

electrical force

solution

we know atomic no of uranium is 92

and charge on electron is = 1.6 × $10^{-19}$ C

and electrical force is express as

electrical force = $\frac{1}{4 \pi \epsilon _o} \frac{q1q2}{r^2}$ .............1

put here value we get

electrical force = $9*10^9 \frac{92*(1.6*10^{-19})^2}{(1.75*10^{-10})^2}$

electrical force = 6.921 × $10^{-7}$ N

so correct option is d) 7.0 x 10^-7 N

5 0

3 years ago

Read 2 more answers

The Eiffel tower in Paris is 300 meters tall on a cold day (T = -24 degrees Celsius), what is its height on a hot day when the t

Varvara68 [4.7K]

Answer:

Length of Eiffel tower, when the temperature is 35 degrees = 300.21 m

Explanation:

Thermal expansion is given by the expression

$\Delta L=L\alpha \Delta T \\$

Here length of Eiffel tower, L = 300 m

Coefficient of thermal expansion, α = 0.000012 per degree Celsius

Change in temperature, = 35 - (-24) = 59degrees Celsius

Substituting

$\Delta L=L\alpha \Delta T= 300\times 0.000012\times 59=0.2124m \\$

Length of Eiffel tower, when the temperature is 35 degrees = 300 + 0.2124 = 300.21 m

3 0

3 years ago

Detlev walks 1000 meters north to the store and walks back 900 meters south to his friends house. The friends house is 100 meter

lilavasa [31]

1000 is the correct answer

3 0

3 years ago

The speed of a box traveling on a horizontal friction surface changes from vi = 13 m/s to vf = 11.5 m/s in a distance of d = 8.5

KiRa [710]

Answer:

0.68 s

Explanation:

We are given that

Initial velocity of box= $u=13m/s$

Final velocity of box=v=11.5 m/s

Distance=d=8.5 m

We have to find the time taken by box to slow by this amount.

We know that

$v^2-u^2=2as$

Substitute the values

$(11.5)^2-(13)^2=2a(8.5)$

$132.25-169=17a$

$-36.75=17a$

$a=\frac{-36.75}{17}=-2.2m/s^2$

We know that

Acceleration= $a=\frac{v-u}{t}$

Substitute the values

$-2.2=\frac{11.5-13}{t}$

$-2.2=\frac{-1.5}{t}$

$t=\frac{1.5}{2.2}=0.68 s$

Hence, the time taken by box to slow by this amount=0.68 s

8 0

3 years ago

What is (9x10^9)(2.6x10^-6)(1.4x10^-6) / 36

Natali [406]

Answer:

0.00091

Explanation:

(9x10^9) (2.6x10^-6) (1.4x10^-6) / 36

(9,000,000,000) (0.0000026) (0.0000014) /36

|

23,400(0.0000014) /36

|

0.03276 /36

|

0.00091

3 0

3 years ago