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Anna35 [415]
3 years ago
6

The process by which the seafloor moves apart at mid-ocean ridges is called _____.

Physics
2 answers:
worty [1.4K]3 years ago
6 0

I think the answer would be C, because to me that's one that makes sense, I hope that I could help, Have a great Thursday!

Ira Lisetskai [31]3 years ago
5 0

Answer:

C. Sea floor spreading.

Explanation:

The geological process by which the tectonic plates separate from each other in the seabed allowing the rise of magma is known as sea floor spreading.

In this process, magma comes into contact with cold water and solidifies rapidly, generating a ridge at the bottom of the ocean, as is shown in the image.

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a man hikes 6.6 km north along a straight path with an average velocity of 4.2 km/h to the north. he rest at a bench for 15 min.
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Answer:

2.6h

Explanation:

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6 0
2 years ago
Can someone please describe surface tension to me. Please don't give me the dictionary definition. Thank you
11111nata11111 [884]


Surface tension - My definition -

It's exactly what it says - The tension of a surface with a liquid (such as water), caused by the attraction of the surfaces layer ---- I hope this helps ---- I actually did research it and got some of this from a dictionary, but I changed some of it, too.... Sorry if this doesn't help :)

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2 years ago
What I the Wannnsjsusbevdyx
Arada [10]
I have no idea what that is, but all of your answers right
3 0
3 years ago
Read 2 more answers
for the primitive yo-yo in fig, to find the downward acceleration of the cylinder and the tension in the string. you can take th
mixas84 [53]

The downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

<h3>Downward acceleration of the cylinder</h3>

The downward acceleration of the solid cylinder is determined from the principle of conservation of angular momentum as shown below;

Iα = Tr

where;

  • I is moment of inertia of the solid cylinder
  • α is angular acceleration of the cylinder
  • T is tension in the string
  • r is length of the string

α = Tr/I

\frac{a}{R} = \frac{Tr}{I} \\\\\frac{a}{R} = \frac{Tr}{\frac{1}{2} MR^2}\\\\\frac{a}{R} =\frac{2Tr}{MR^2} \\\\a = \frac{2Tr}{MR}

where;

  • a is the downward acceleration of the solid cylinder
  • R is radius of the cylinder

Thus, the downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

Learn more about acceleration here: brainly.com/question/605631

#SPJ1

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1 year ago
Which imaging techniques capture real-time images?
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Sonography and fluroscopy capture real time image.
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3 years ago
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