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Anna35 [415]
3 years ago
6

The process by which the seafloor moves apart at mid-ocean ridges is called _____.

Physics
2 answers:
worty [1.4K]3 years ago
6 0

I think the answer would be C, because to me that's one that makes sense, I hope that I could help, Have a great Thursday!

Ira Lisetskai [31]3 years ago
5 0

Answer:

C. Sea floor spreading.

Explanation:

The geological process by which the tectonic plates separate from each other in the seabed allowing the rise of magma is known as sea floor spreading.

In this process, magma comes into contact with cold water and solidifies rapidly, generating a ridge at the bottom of the ocean, as is shown in the image.

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What is measurement?​
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Answer:

How long or wide something is

Explanation:

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Compare and contrast the general characteristics of a gas giant planet and one of the inner planets (such as Mercury, Earth, Ven
yKpoI14uk [10]
The gas planets usually have extremely high gravitational pulls, the surface isn't solid (since its a gas planet), and gas planets are larger than the inner planets. 
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3 years ago
The acceleration due to gravity is higher on juniper Than on earth. The mass and weight of rock on juniper compared to that on e
soldier1979 [14.2K]

Answer:

2.5 times higher then that on the Earth

Explanation:

Gravity is higher on Jupiter then on Earth because Jupiter is much bigger, because of it's mass compared to Earth the gravity on Jupiter is about 2.4 - 2.5 times higher then Earths surface gravity which means a rock on Jupiter would be around "2.4 - 2.5 times as heavier then it would be on Earth."

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3 0
2 years ago
If you increase the size of the resistor and keep the voltage the same, what will happen to the current
Grace [21]

Answer:

If voltage is kept constant across the resistor itself, it' current will reduce. If the resistance is part of oscillator circuit, frequency response will change. If it is in series with capacitor or inductor, it will change the damping effect.

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8 0
3 years ago
An airplane is flying through a thundercloud at a height of 2000 m (This is a very dangerous thing to do because of updrafts, tu
Doss [256]

Answer:

400000\ \text{N/C}

Explanation:

q_1 = Charge at 3000 m = 40 C

q_2 = Charge at 1000 m = -40 C

r_1 = 3000 m

r_2 = 1000 m

k = Coulomb constant = 9\times10^9\ \text{Nm}^2/\text{C}^2

Electric field due to the charge at 3000 m

E_1=\dfrac{k|q_1|}{r_1^2}\\\Rightarrow E_1=\dfrac{9\times 10^9\times 40}{3000^2}\\\Rightarrow E_1=40000\ \text{N/C}

Electric field due to the charge at 1000 m

E_2=\dfrac{k|q_2|}{r_2^2}\\\Rightarrow E_2=\dfrac{9\times 10^9\times 40}{1000^2}\\\Rightarrow E_2=360000\ \text{N/C}

Electric field at the aircraft is E_1+E_2=40000+360000=400000\ \text{N/C}.

7 0
3 years ago
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