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yulyashka [42]
2 years ago
15

How can water boil without heat?​

Physics
1 answer:
kaheart [24]2 years ago
3 0

Answer:

Put water at room temperature into a vacuum chamber and begin removing the air. Eventually, the boiling temperature will fall below the water temperature and boiling will begin without heating. Or if you want to be easy but messy, add dry ice to a bowl of water and watch how the water starts to boil.

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Helppppppp its exam ​
UkoKoshka [18]

Answer:

a. 240.2 C

Explanation:

7 0
3 years ago
A hot-air balloon is ascending at the rate of 10 m/s and is 74 m above the ground when a package is dropped over the side. (a) H
Reika [66]

Answer:

The answer to your question is:

a)  t1 = 2.99 s ≈ 3 s

b)  vf = 39.43 m/s

Explanation:

Data

vo = 10 m/s

h = 74 m

g = 9.81 m/s

t = ?   time to reach the ground

vf = ?   final speed

a)    h = vot + (1/2)gt²

     74 = 10t + (1/2)9.81t²

     4.9t² + 10t -74 = 0                  solve by using quadratic formula

   

   t = (-b ± √ (b² -4ac) / 2a

   t = (-10 ± √ (10² -4(4.9(-74) / 2(4.9)

   t = (-10 ± √ 1550.4 ) / 9.81

  t1 = (-10 + √ 1550.4 ) / 9.81               t2 = (-10 - √ 1550.4 ) / 9.81

  t1 = (-10 ± 39.38 ) / 9.81                    t2 = (-10 - 39.38) / 9.81

   t1 = 2.99 s ≈ 3 s                               t2 = is negative then is wrong there are

                                                                   no negative times.

b) Formula vf = vo + gt

                  vf = 10 + (9.81)(3)

                  vf = 10 + 29.43

                  vf = 39.43 m/s

4 0
2 years ago
A sprinter starts from rest and reaches a speed of 15 m/s in 4.25 s. Find his acceleration
kakasveta [241]

Answer:

a=3.53 m/s^2

Explanation:

Vo=0 m/s (because he is not moving at the start)

V1=15 m/s

t= 4.25 s

a = (V1-Vo) / t = 15/4.25 = 3.53 m/s^2

5 0
2 years ago
Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 re
alexgriva [62]

Answer:

\frac{Ie}{lm} = 1.10*10^{-3}

Explanation:

GIVEN DATA:

Engine operating speed nf = 8325 rev/min

engine angular speed ni= 12125 rev/min

motorcycle angular speed N_m= - 4.2 rev/min

ratio of moment of inertia of engine to motorcycle is given as

\frac{Ie}{lm} = \frac{-N}{(nf-ni)}

\frac{Ie}{lm} = \frac{-(-4.2)}{(12125 - (8325))}

\frac{Ie}{lm} = 1.10*10^{-3}

5 0
3 years ago
Read 2 more answers
1+5-(-5 - 1) whats the answer​
vladimir2022 [97]

Answer:

12

Explanation:

6 0
2 years ago
Read 2 more answers
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