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Elden [556K]
3 years ago
15

Do we have free will or is everything predestined?

Physics
2 answers:
S_A_V [24]3 years ago
4 0
Predestination, in theology, is the doctrine that all events have been willed by God, usually with reference to the eventual fate of the individual soul. Explanations of predestination often seek to address the "paradox of free will", whereby God's omniscience seems incompatible with human free will.
Harman [31]3 years ago
3 0

Answer: yes we have free will

Explanation: yes we have free will but there are some things that you cant stop. like your death. on such cases they are like predestined. But that dont mean that there is a GOD who decides things. Its the nature.

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A plate drops onto a smooth floor and shatters into three pieces of equal mass.Two of the pieces go off with equal speeds v at r
Firlakuza [10]

Answer:

Speed of the this part is given as

v_3 = \sqrt2 v

Also the direction of the velocity of the third part of plate is moving along 135 degree with respect to one part of the moving plate

Explanation:

As we know by the momentum conservation of the system

we will have

P_1 + P_2 + P_3 = P_i

here we know that

P_1 = P_2

the momentum of two parts are equal in magnitude but perpendicular to each other

so we will have

P_1 + P_2 = \sqrt{P^2 + P^2}

P_1 + P_2 = \sqrt2 mv

now from above equation we have

P_3 = -(P_1 + P_2)

mv_3 = -(\sqrt 2 mv)

v_3 = \sqrt2 v

Also the direction of the velocity of the third part of plate is moving along 135 degree with respect to one part of the moving plate

6 0
3 years ago
What is the speed of a truck that travels 60 km in 20 minutes
Alexxandr [17]
Formula:
Speed = Distance ÷ Time

Solution:
Speed = 60 ÷ 20
= 3km/min
6 0
3 years ago
A block of aluminium of density 7900 kg/m3 has a volume of 250 cm. Find the<br>mass of the block.​
pashok25 [27]

Answer:

mass of block=2.7 gm

Explanation:

concept: Density=mass/volume

given:ρ=2700 kg/m^3 and v=250 cm^3 (in cm^3 not in m^3)

=> v= convert cm^3 to m^3

there fore= 1 cm^3=1 cm*1 cm*1 cm

i.e 1 cm^3=1/100*1/00*1/100 m^3 => 1 cm^3=1/1000000 m^3

ρ=m/v

=>mass=ρ*volume

=>mass=2700*1/10^-6

=>mass=2.7*10^-3 kg =>2.7 gm

8 0
3 years ago
The resolving power of a microscope is proportional to the wavelength used. A resolution of 1.0 10-11 m (0.010 nm) would be requ
Anon25 [30]

Answer:

K = 13448.64eV

Explanation:

(a) In order to calculate the kinetic energy of the electrons, to "see" the atom, you take into account that the wavelength of the electrons must be of the order of the resolution required (0.010nm).

Then, you first calculate, by using the Broglies' relation, the momentum of the electron associated to a wavelength of 0.010nm:

p=\frac{h}{\lambda}       (1)

p: momentum of the electron

h: Planck's constant = 6.626*10^-34 Js

λ: wavelength = 0.010nm

You replace the values of the parameters in the equation (1):

p=\frac{6.262*10^{-34}Js}{0.010*10^{-9}m}=6.262*10^{-23}kg\frac{m}{s}

With this values of the momentum of the electron you can calculate the kinetic energy of the electron by using the following formula:

K=\frac{p^2}{2m}    (2)

m: mass of the electron = 9.1*10^-31 kg

K=\frac{(6.262*10^{-23}kgm/s)^2}{2(9.1*10^{-31}kg)}=2.15*10^{-15 }J

In electron volts you obtain:

2.15*10^{-15}J*\frac{6.242*10^{18}eV}{1J}=13448.64eV

The kinetic energy required for the electrons must be, at least, of 13448.64 eV

5 0
3 years ago
A hydrogen atom contains a single electron that moves in a circular orbit about a single proton. Assume the proton is stationary
riadik2000 [5.3K]

Answer:

Radius between electron and proton= 6.804\times 10^{-10}m

Explanation:

The motion of the electron is carried out in the orbit due to the balancing of the electrostatic force between the proton and the electron and the centripetal force acting on the electron.

The electrostatic force is given as = \frac{kq_1q_2}{r^2}

Where,

k = coulomb's law constant (9×10⁹ N-m²/C²)

q₁ and q₂  = charges = 1.6 × 10⁻¹⁹ C

r = radius between the proton and the electron

Also,

Centripetal force on the moving electron is given as:

=\frac{m_eV^2}{r}

where,

m_e = mass of the electron (9.1 ×10⁻³¹ kg)

V = velocity of the moving electron (given: 6.1 ×10⁵ m/s)

Now equating both the formulas, we have

\frac{kq_1q_2}{r^2} = \frac{m_eV^2}{r}

⇒r = \frac{kq_1q_2}{m_eV^2}

substituting the values in the above equation we get,

r = \frac{9\times 10^{9}\times (1.6\times 10^{-19})^2}{9.1\times 10^{-31}\times (6.1\times 10^5)^2}

⇒r = 6.804\times 10^{-10}m

3 0
3 years ago
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