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prisoha [69]
3 years ago
7

What would happen if the amount of light reaching the Earth from the sun were cut in half? Predict what the climate and life wou

ld be like here on Earth. How would humans respond to this change?
Physics
1 answer:
kicyunya [14]3 years ago
5 0
A lot would happen depends on which perspective you look at it from. Less incoming solar radiation means that there is a greater possibility of the surface temperature of earth reducing. there would be a cooling effect. And it could be major cooling in certain part of the world depending on milankovitch cycles. We know that the amount of light or solar radiation that reaches the earth is unequal in different parts of the world because of the obliquity, eccentricity, and precession of the earth. But, in general you would most likely see a cooling trend around the world and in some parts it would be extreme. In Canada or in the North is general, winters would become even more cooler or colder... winters would become longer perhaps, And summers would 've cooler. on the contrary to what most believe, you would most likely see a decline in precipitation such as snow or rain because this is mostly caused or intensified by warming temperatures. Life would be probably very similar to that of the Pleistocene epoch. how would humans respond to this change... Well most likely they would try to use their tech to control weather because they already do to a smaller proportion.

hope that helps a bit! :)
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Consider an eraser, weighing 20g, sitting 5cm from the center of a turntable (flat disk attached to a motor which can spin the d
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Answer:

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B. Centripetal Force

Explanation:

20 g = 0.02 kg

5 cm = 0.05 m

Let g = 9.8 m/s2

A.The friction force acting on the eraser is the product of normal force and its coefficient:

F_f = N\mu = mg\mu = 0.02*9.8*0.1 = 0.0196 N

For the eraser to begin slipping, its centripetal acceleration must win over the acceleration created by friction force, which is

a_f = F_f / m = 0.0196 / 0.02 = 0.98 m/s^2 = a_c

We can calculate the angular velocity from this:

a_c = \omega^2 r

where r = 0.05 is the radius of rotation, which is distance from the center to the eraser

\omega^2 = a_c/r = 0.98 / 0.05 = 19.6

\omega = \sqrt{19.6} = 4.43 rad/s

If it spins and angle of 4.43 rad per second then for every minute (60 seconds) it would spin an angle of 4.43 * 60 = 265.6 rad/min

Since 1 revolution is 2π rad, then in a minute it would spin 265.6 / 2π = 42.3 revolution/minute

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Answer:

More work done with less power

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