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nydimaria [60]
3 years ago
8

A car of mass m goes around a banked curve of radius r with speed v. If the road is frictionless due to ice, the car can still n

egotiate the curve if the horizontal component of the normal force on the car from the road is equal in magnitude to _____________.
Physics
1 answer:
Sholpan [36]3 years ago
5 0

Answer:

horizontal component of normal force is equal to the centripetal force on the car

Explanation:

As the car is moving with uniform speed in circle then the force required to move in the circle is towards the center of the circle

This force is due to friction force when car is moving in circle with uniform speed

Now it is given that car is moving on the ice surface such that the friction force is zero now

so here we can say that centripetal force is due to component of the normal force which is due to banked road

Now we have

N sin\theta = \frac{mv^2}{R}

N cos\theta = mg

so we have

v = \sqrt{Rg tan\theta}

so this is horizontal component of normal force is equal to the centripetal force on the car

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People living at Earth’s equator are traveling at a constant speed of about 1,670 km/h as Earth spins on its axis. What are thes
Vlada [557]
The people living around the equator experience acceleration. Acceleration is the change in speed or/and direction. When on a rotating body, the speed does not change it is only the direction that changes as it rotates.When on a rotating body you do not have to change speed but only direction. In a normal situation when you are traveling on a circle you will never have a straight line.
4 0
3 years ago
A string under a tension of 36 N is used to whirl a rock in a horizontal circle of radius 3.6 m at a speed of 16.12 m/s. The str
ExtremeBDS [4]

Answer:

6010.457N

Explanation:

Centripetal acceleration = a= V²/R

At a radius of 3.6m and velocity of 16.12m/s,

Acceleration is

a = 16.12²/ 3.6 = 72.182 m/s²

Force = Mass (m) * Acceleration (a)

36 = m * 72.182

m = 36/72.182

At breaking point

Radius = 0.468 m and Velocity = 75.1 m/s

a = V²/R = 75.1²/0.468

a = 12051.3 m/s

F = Mass(m) * Acceleration (a)

F = m * 12051.3

m = F/ 12051.3

Settings the ratio of mass equal

m = m

=> 36/72.182 = F/12051.3

F = 12051.3 * 36/72.182

F = 6010.457N

3 0
3 years ago
Mathew throws a ball straight up in the air. it rises for a period of time and then begins to drop. At which points in the balls
Allushta [10]

Answer:   The greatest force of gravity on the ball will occur at the point when the ball is near to hit the ground ... hope this helps have a good day :P

3 0
2 years ago
The free body diagram shows a box being pulled to the left up a 25-degree incline
Greeley [361]
The question is incomplete but still I answer to assume your thinking.
The picture is attached below!.
Here,
F is the force with which you pull up the incline.
N is the normal force.
w is the weight acting downward.
Axis are mentioned in the attached picture.
Concept:
You can see there is no movement of object in the y-direction that means acceleration is zero in y-direction, sum of all the forces in y-direction equal to zero.
According to newton second law,
<span>∑ F = ma
</span>As, acceleration is zero in y-direction, so right hand side is zero in the above equation.
<span>∑ F = 0</span>
N-wcosθ=0 
N= m*g*cos25°
N= m*(9.8)*(0.9063)
N= 8.8817*m
By putting the value of mass(m)(not given in the question) you will get the answer.
Hopefully, this is the answer of your question.


5 0
3 years ago
Read 2 more answers
Which type of muscle cell can have multiple nuclei
s344n2d4d5 [400]

Answer:

Skeletal muscle cells

Explanation:

Skeletal muscle cells are long, cylindrical, and striated. They are multi-nucleated meaning that they have more than one nucleus. This is because they are formed from the fusion of embryonic myoblasts.

pls mark me the brainliest

7 0
2 years ago
Read 2 more answers
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