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nydimaria [60]
3 years ago
8

A car of mass m goes around a banked curve of radius r with speed v. If the road is frictionless due to ice, the car can still n

egotiate the curve if the horizontal component of the normal force on the car from the road is equal in magnitude to _____________.
Physics
1 answer:
Sholpan [36]3 years ago
5 0

Answer:

horizontal component of normal force is equal to the centripetal force on the car

Explanation:

As the car is moving with uniform speed in circle then the force required to move in the circle is towards the center of the circle

This force is due to friction force when car is moving in circle with uniform speed

Now it is given that car is moving on the ice surface such that the friction force is zero now

so here we can say that centripetal force is due to component of the normal force which is due to banked road

Now we have

N sin\theta = \frac{mv^2}{R}

N cos\theta = mg

so we have

v = \sqrt{Rg tan\theta}

so this is horizontal component of normal force is equal to the centripetal force on the car

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Answer: A a decrease of 8000

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Use the graph for both answers.
Natasha2012 [34]

1. A. 6.00 sec

The graph shows the velocity of an object (y-axis) versus the time (x-axis). In order to find when the magnitude of the velocity reaches 36.00 km/h, we should find the time t (x-coordinate) at which the velocity (y-coordinate) is 36.

By looking at the graph, we see that this occurs when t=6.00 s.


2. A. positive acceleration

In a velocity-time graph like this one, the slope of the curve corresponds to the acceleration of the object. In fact, acceleration is defined as:

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3 years ago
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A batter hits a baseball m = 0.41 kg from rest with a force of F = 81
WITCHER [35]

Answer:

7.0s

Explanation:

Mass = 0.41kg

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t = 0.22s

¤ = 29°

Lo = 86m

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81 * 0.22 = 0.41 * v

Vo = 17.82 / 0.41

Vo = 43.46m/s

Vx= velocity across horizontal plane

Vy = velocity across vertical plane

Vx = Vo * cos ¤

Vy = Vo * sin ¤

Vx = 43.46 * cos 30° = 37.64 m/s

Vy = 43.46 sin 30° = 21.73 m/s

Distance travelled across the vertical plane,

L = Lo + Vy *t + ½gt²

0 = 86 + 21.73t - 4.9t²

4.9t² - 21.73t - 86 = 0

Solving for t in the quadratic equation,

t = 6.96 or -10.04

Using the positive root since time can't be negative, t = 6.96 approximately 7.0s

4 0
3 years ago
Suppose that during a storm the force of the wind blowing against a skyscraper can be expressed by the vector , where each measu
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Then, we can calculate the total magnitude of this force as:

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marysya [2.9K]

Answer:

0.739

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coefficient of static friction = (7.2567 × m) / (9.81 × m)

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4 0
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