3. What distance will a car, traveling 65 km/hr, cover in 3.0 hrs? (195 km)
1 answer:
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Answer:
Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.
Explanation:
We have been given that the average distance of Enceladus from Saturn is 238,000 km; the average distance of Titan from Saturn is 1,222,000 km.
We will use Kepler's Law to solve our given problem.
Upon substituting our given values, we will get:
Taking square root of both sides, we will get:
This implies that time period of Titan about Sturn is 11.634 times more compared to time period of Enceladus about Saturn.
So, basically Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.
Answer:
a) v = 18.86 m / s, b) h = 8.85 m
Explanation:
a) For this exercise we can use the conservation of energy relations.
Starting point. Like the compressed spring
Em₀ = K_e + U = ½ k x² + m g x
the zero of the datum is placed at the point of the uncompressed spring
Final point. With the spring if compress
Em_f = K = ½ m v²
how energy is conserved
Em₀ = Em_f
½ k x² + m g x = ½ m v²
v² = x² + 2gx
let's reduce the magnitudes to the SI system
m = 500 g = 0.500 kg
x = -45 cm = -0.45 m
the negative sign is because the distance in below zero of the reference frame
let's calculate
v² = 0.45² + 2 9.8 (- 0.45)
v = √355.68
v = 18.86 m / s
b) For this part we use the conservation of energy with the same initial point and as an end point at the point where the rock stops
Em_f = U = m g h
Em₀ = Em_f
½ k x²2 + m g x = m g h
h = ½ x² + x
let's calculate
h = - 0.45
h = 8.85 m
measured from the point where the spring is uncompressed
Answer:
a)
b)
Explanation:
L = inductance of the Inductor = 3.14 mH = 0.00314 H
C = capacitance of the capacitor = 5.08 x 10⁻⁶ F
a)
f = frequency = 55.7 Hz
Impedance is given as
b)
f = frequency = 11000 Hz
Impedance is given as