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Anettt [7]
4 years ago
12

Roberto makes a graphic organizer to compare fusion nuclear reactions and fission nuclear reactions. A venn diagram with 2 inter

secting circles The circle on the left is labeled fusion. The circle on the right is labeled fission. There is a Z in the fission circle. There is an Y in the intersecting area. There is an X in the fusion circle. Which labels belong in the regions marked X, Y, and Z?
Physics
2 answers:
Schach [20]4 years ago
9 0

Answer:

The second one

Explanation:

The second one is joining so it is the one which belongs to X, first one belongs to Z

vekshin14 years ago
5 0

Answer:

D on edge

Explanation:

edge202020

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What is correlation of productivity and positive attitude
Ivahew [28]

For example, when you are at work. If you love what you are doing, you will feel happy, contented and your mind will be at ease. It can give you a positive attitude towards your work no matter how difficult or easy it may be. After persevering your positivity, you will still continue and do what you really love by being productive.

3 0
4 years ago
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There are several forms of energy. Which of the following is not a form of energy?
Evgen [1.6K]
A. Is the right answer.
8 0
3 years ago
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Three deer, A, B, and C, are grazing in a field. Deer B is located 62m from deer A at an angle of 51° north of West. Deer C is l
Anna71 [15]

Set deer A's position to be the origin. Let c be the distance from deer A to deer C. We're given that deer B is 95 m away from deer C, which means the length of the vector B-C is 95 (or C-B). Then

|B-C|^2=(B-C)\cdot(B-C)=B\cdot B-2B\cdot C+C\cdot C=|B|^2-2B\cdot C+|C|^2

|B-C|^2=|B|^2-2|B||C|\cos(180-77-51)^\circ+c^2

95^2=62^2-2(62)(c)\cos52^\circ+c^2

c^2-124\cos52^\circ c-5181=0\implies c=120\,\mathrm m

8 0
4 years ago
One positve and one negative charhe jave a force of -5. 00 N between them. If the force changed to -170 N , by what factor did t
stepladder [879]

Answer:

The distance is shortenend by factor .1715

Explanation:

5 n  = 1/r^2

sqrt (1/5) = r

170 n  = 1 / ( x sqrt(1/5))^2

(xsqrt 1/5)^2 = 1/170

x sqrt 1/5  = .076696

x = .1715    

5 0
2 years ago
This is the change in kinetic energy of a system in which a 16 kg object moving at 25 m/s slows to a velocity of 20 m/s
Dennis_Churaev [7]

The kinetic energy of an object is given by

KE = 0.5mv²

where m is the mass and v is the velocity.

To calculate the change in kinetic energy...

Initial KE:

KEi = 0.5mVi²

where Vi is the initial velocity.

Final KE:

KEf = 0.5mVf²

where Vf is the final velocity.

ΔKE = KEf - KEi

ΔKE = 0.5mVi² - 0.5mVf²

ΔKE = 0.5m(Vf²-Vi²)

Given values:

m = 16kg

Vi = 25m/s

Vf = 20m/s

Plug in the given values and solve for ΔKE:

ΔKE = 0.5×16×(20²-25²)

ΔKE = -1800J

5 0
3 years ago
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