Answer:
what is the quetion.......
Explanation:
<u>Answer:</u> The volume of the container is 
<u>Explanation:</u>
To calculate the volume of water, we use the equation given by ideal gas, which is:
or,
where,
P = pressure of container = 200 kPa
V = volume of container = ? L
m = Given mass of water = 2.61 kg = 2610 g (Conversion factor: 1kg = 1000 g)
M = Molar mass of water = 18 g/mol
R = Gas constant = 
T = temperature of container = ![200^oC=[200+273]K=473K](https://tex.z-dn.net/?f=200%5EoC%3D%5B200%2B273%5DK%3D473K)
Putting values in above equation, we get:
Converting this into cubic meter, we use the conversion factor:
So, 
Hence, the volume of the container is
A) The triple point
The triple point of a system is the thermodynamic point where the pressure, composition and temperature are maintained at a specific value and all three phases of that substance, solid, liquid and gas, coexist. This equilibrium is disturbed if any of the above mentioned variables are changed. The degree of freedom at the triple point is described as being zero.
Answer:
0.1 m C6H12O6 < 0.1 m NaCl < 0.1 m Cu(NO3)2 < 0.1 m Fe(NO3)3
Explanation:
Step 1: Data given
ΔTb = Kb*m*i
⇒with Kb = 0.512°C/m
⇒with m = molality
⇒with i = Van't hoff factor = the number of particles into which the solute dissociates
a. 0.1 m NaCl
⇒ molality = 0.1 molal
⇒ i(NaCl) = 2 ( dissociates in Na+ and Cl-)
0.1 * 2 = 0.2
b. 0.1 m Cu(NO3)2
⇒ molality = 0.1 molal
⇒ i(Cu(NO3)2) = 3 ( dissociates in Cu^2+ and 2NO3-)
0.1 * 3 = 0.3
c. 0.1 m C6H12O6
⇒ molality = 0.1 molal
⇒ i(C6H12O6) = 1 ( doesn't dissociate in water)
0.1 * 1 = 0.1
d. 0.1 m Fe(NO3)3
⇒ molality = 0.1 molal
⇒ i(Fe(NO3)3) = 4 ( dissociates in Fe^3+ and 3NO3-)
0.1 * 4 = 0.4
0.1 m C6H12O6 < 0.1 m NaCl < 0.1 m Cu(NO3)2 < 0.1 m Fe(NO3)3
