Answer:
Volume = 72.7272
Explanation:
if only pressure and volume change, then we can do some simple math to find the answer.
2 x 10 ^ 6 times 1 x 10 ^-5 = 20
pressure and volume must equal 20
20 = 0.275 x volume
20 / 0.275 = new volume
I don't remember significant digits but your volume is 72.72727272 just repeated
Answer:
1.373 mol H₂O
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
24.75 g H₂O
<u>Step 2: Identify Conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
<u />
= 1.37347 mol H₂O
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
1.37347 mol H₂O ≈ 1.373 mol H₂O
Answer:
The gas that Dr. Brightguy added was O₂
Explanation:
Ideal Gases Law to solve this:
P . V = n . R . T
Firstly, let's convert 736 Torr in atm
736 Torr is atmospheric pressure = 1 atm
20°C = 273 + 20 = 293 T°K
125 mL = 0.125L
0.125 L . 1 atm = n . 0.082 L.atm / mol.K . 293K
(0.125L .1atm) / (0.082 mol.K /L.atm . 293K) = n
5.20x10⁻³ mol = n
mass / mol = molar mass
0.1727 g / 5.20x10⁻³ mol = 33.2 g/m
This molar mass corresponds nearly to O₂
Answer:
215 amu
Explanation:
In the reactants:
There is 1 iron atom, 3 chlorine atoms, 6 hydrogen atoms and 3 oxygen atoms:
- Fe: 56 × 1 = 56
- Cl: 35 × 3 = 105
- H: 1 × 6 = 6
- O: 16 × 3 = 48
56 + 105 + 6 + 48 = 215 amu
Hope this helps!
Answer: Originally viewed as a single event, the Taconic orogeny is now known to consist of at least three episodes. The first took place in the Early Ordovician Epoch near Maine and Newfoundland. The second was centred on eastern Tennessee in the Middle Ordovician Epoch.
