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3 years ago

Which has a greater volume, 10 grams of water or 10 grams of acetone?

Chemistry

1 answer:

WINSTONCH [101]3 years ago

6 0

Density is defined as the ratio of mass to the volume.

Density = $\frac{Mass}{Volume}$ (1)

Mass of water = 10 grams

Mass of acetone = 10 grams

Density of water = 1 $\frac{g}{cm^{3}}$

Density of acetone = 0.7857 $\frac{g}{cm^{3}}$

Put the value of density of water and its mass in equation (1)

1 $\frac{g}{cm^{3}}$ = $\frac{10 g}{volume}$

Volume of water = 10 $cm^{3}$

Put the value of density of acetone and its mass in equation (1)

0.7857 $\frac{g}{cm^{3}}$ = $\frac{10 g}{volume}$

Volume of acetone = 12.72 $cm^{3}$

Thus, volume of acetone is more than volume of water because the density of acetone is lower.

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Read 2 more answers

How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m

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<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

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$pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of acetic acid = 4.74

$[CH_3COONa]=?mol$

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Putting values in above equation, we get:

$5=4.74+\log(\frac{[CH_3COONa]}{0.200})$

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$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

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Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

$0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g$

Hence, the mass of sodium acetate that must be added is 30.23 grams

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