Question

When potassium hydroxide and barium chloride react, potassium chloride and barium hydroxide are formed. The balanced equation for this reaction is __________.A. KH + BaCl --> KCl + BaH
B. KOH + BaCl --> KCl + BaOH
C. 2KOH + BaCl₂ --> 2KCl + Ba(OH)₂
D. KOH + BaCl₂ --> KCl₂ + BaOH

Answer 1

Answer: C.

2KOH + BaCl2 => 2KCl + Ba(OH)2

Explanation:

There are 2 atoms of O and H in Ba(OH)2 in the product so to balance we put 2 on KOH. Then balance K by adding 2 in KCl to have equal number of atoms for K and Cl in both the reactant and product side. Barium have 1 atom on the reactant and in the product.

Answer 2

Answer:

The answer to your question is letter C.

Explanation:

Reaction

Potassium hydroxide = KOH

Barium chloride = BaCl₂

Potassium chloride = KCl

Barium hydroxide = Ba(OH)₂

           KOH   +   BaCl₂    ⇒    KCl   +   Ba(OH)₂

         Reactant        Elements       Products

               1                     K                      1

               1                     Ba                    1

               2                    Cl                     1  

                1                     H                    2

                1                     O                    2

The reaction is unbalanced

        2KOH   +   BaCl₂    ⇒   2KCl   +   Ba(OH)₂

         Reactant        Elements       Products

               2                     K                     2

               1                     Ba                    1

               2                    Cl                     2  

               2                      H                    2

               2                     O                    2

Now, the reaction is balanced