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sammy [17]
3 years ago
13

Describe a method to investigate how the temperature changes when different masses of ammonium

Chemistry
1 answer:
rewona [7]3 years ago
4 0

Answer:

Decrease temperature with increase in ammonium nitrate concentration.

Explanation:

The temperature changes when different masses of ammonium nitrate are dissolved in water because the ammonium nitrate takes energy from the surrounding water environment for the breaking of ionic bonds as a result the temperature of water decreases. When more concentration of ammonium nitrate is added to water, more decrease occur in temperature of water and the water becomes cold.

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A ph of 2 indicates a
alekssr [168]
Nope mate I have no clue
5 0
3 years ago
How do you determine the chemical reactivity for metals by using the periodic table?
vesna_86 [32]

Answer:

Chemical reactivity increases down a group and decreases from left to right of a period.

Explanation:

The higher the ionization energy is, the lower the reactivity is. Since the ionization energy is highest in the top right corner of the periodic table, we can assume that the most reactive elements are in the opposite bottom left corner. This is because the electrons that react are farther away from the nucleus thus experience less attraction to the nucleus (called nuclear shielding). Therefore their electrons are more easily removed than elements that don't ecperience nuclear shielding.

4 0
4 years ago
Which element has exactly five electrons in the highest principal energy level (the outer shell)?
kap26 [50]
Boron (B) has 3 electrons in the outer shell.
Barium (Ba) has 2 electrons.
Phosphorus (P) has 5 electrons.
Manganese (Mn) has 2 electrons.

The answer is C) P (phosphorus).
4 0
4 years ago
The molar volume of a certain solid is 142.0 cm3 mol−1 at 1.00 atm and 427.15 k, its melting temperature. the molar volume of th
kotykmax [81]

Answer:

\Delta _{fus}H=3255.3J/mol

\Delta _{fus}S=7.62\frac{J}{mol*K}

Explanation:

Hello,

Clausius Clapeyron equation is suitable in this case, since it allows us to relate the P,T,V behavior along the described melting process and the associated energy change. Such equation is:

\frac{dp}{dT}=\frac{\Delta _{fus}H}{T\Delta _{fus}V}

As both the enthalpy and volume do not change with neither the temperature nor the pressure for melting processes, its integration turns out:

p_2-p_1=\frac{\Delta _{fus}H}{\Delta _{fus}V}ln(\frac{T_2}{T_1} )

Solving for the enthalpy of fusion we obtain:

\Delta _{fus}H=\frac{(p_2-p_1)(V_2-V1)}{ln(\frac{T_2}{T_1})} =\frac{(11.84atm-1.00 atm)(156.6cm^3/mol-142.0cm^3/mol)}{ln(\frac{429.26K}{427.15K} )} \\\\\Delta _{fus}H=32127.3atm*cm^3/mol*\frac{101325Pa}{1atm}*(\frac{1m}{100cm} )^3\\\Delta _{fus}H=3255.3J/mol

Finally the entropy of fusion is given by:

\Delta _{fus}S=\frac{\Delta _{fus}H}{T_1} =\frac{3255.3J/mol}{427.15K}\\ \\\Delta _{fus}S=7.62\frac{J}{mol*K}

Best regards.

5 0
3 years ago
A gas takes up a volume of 35 L, and has a pressure of 4.8 atm. What is the new pressure of
joja [24]

Answer:

7.3 atm

Explanation:

- Use the formula P1V1 = P2V2

- Rearrange formula and then plug in values.

- Hope this helped! Let me know if you need more help or a further explanation.

3 0
3 years ago
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