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2 years ago

Abbey always gets zits on her chin and she can't figure out

1 answer:

6 0

Experiment has to do with the examination of the relationship between the dependent variable and the independent variable.

<h3>What is an experiment?</h3>

The term experiment has to do with the examination of the relationship between the dependent variable and the independent variable. In this case, the independent variable is the variable that we can manipulate while the dependent variable the one that changes when we manipulate the independent variable.

Let us now identify the variables in the experiment;

independent variable; the type of product used

constant variable; length of time that the product is used

Hypothesis; The Zits could be cleared from her face by a skin care product

The control group is the washing with water

The experimental group is the washing with a product

The constant is the face on which the product s used.

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Missing parts;

Abbey always gets zits on her chin and she can’t figure out the best method to get rid of them. She decides to test several products to see which clears her face up fastest: washing with soap and water, washing with an acne face wash from the pharmacy, and washing her face with organic oils. For one week she just washes her face with water. The next week she washes every day with soap and water. The following week she uses the acne wash, and the last week she uses the organic oils. Each week she records the number of zits she has on her chin at the end of the day. What is the independent variable? What is the constant variable? What is the hypothesis? What is the control group? What is the experimental group? What is the constant?

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3 years ago

What volume of o2 is needed to react fully with 720. Ml of nh3

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Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.

<h3>What is volume?</h3>

Volume is the area occupied by the substance and is the ratio of the mass to the density.

At STP, 1 mole of gas occupies 22.4 L of volume

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Volume of ammonia reacted = 0.720 L

The combustion reaction is shown as,

$\rm 4NH_{3} + 5O_{2} \rightarrow 4NO +6H_{2}O$

From the stoichiometry of the reaction, it can be said that,

$(4 \times 22.4)$ L of ammonia reacts with $(5 \times 22.4)$ L of oxygen gas.

So, 0.720 L of ammonia will react with:

$\dfrac{ (5 \times 22.4)}{(4 \times 22.4)} \times 0.720 = 0.9 \;\rm L$

Therefore, the volume of oxygen required is 900 mL.

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2 years ago

Complete the following precipitation reactions with balanced molecular, total ionic, and net ionic equations:

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Molecular equation

Hg₂(NO₃)₂ (aq) + KI(aq) ⇒Hg₂I₂(s) + 2KNO₃(aq)

Total Ionic equation

Hg²⁺(aq) + 2NO³⁻(aq) + 2K⁺aq) ⇒Hg₂I₂(s) + 2K⁺(aq) + NO³⁻ (aq)

Net Ionic equation

Hg²⁺(aq) + 2I⁻(aq) ⇒ Hg₂I₂(s)

<h3>What is the molecular equation?</h3>

Sometimes, a balanced equation is all that is used to refer to a chemical equation. Any ionic substances or acids are represented using their chemical formulas as neutral compounds in a molecular equation. Each substance's state is described in parenthesis after the formula. A complete ionic equation also contains the spectator ions, whereas a net ionic equation just displays the chemical species that are involved in a reaction.

The steps listed below can be used to determine the net ionic equation for a specific reaction:

Include the states of each chemical in the balanced molecular equation for the reaction.

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1 year ago

For the reaction PC15 (8) PC13 (g) + Cl2 (g) K = 0.0454 at 261 °C. If a vessel is filled with these gases such that the initial

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The correct answer is B.

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Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

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$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$