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serious [3.7K]
3 years ago
13

Definition of diameter?

Chemistry
1 answer:
astra-53 [7]3 years ago
3 0

Answer:

a straight line passing from side to side through the center of a body or figure, especially a circle or sphere.

Explanation:

a straight line passing from side to side through the center of a body or figure, especially a circle or sphere.

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Each element consists of only one type of atom.<br> A.) True<br> B.) False
natima [27]
False there are different configurations of atoms called isotopes
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Barium phosphide Ba3P2 BaP Ba3PO4
Novosadov [1.4K]

Answer:

It A(Ba3P2)

Explanation:

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A galvanic cell generates a cell potential of 0.32V when operated under standard conditions according to the reaction above. Whi
Ugo [173]

The complete question is shown in the image attached to this answer.

Answer:

C

Explanation:

Let us quickly remember that the EMF of a cell under non standard conditions in given by the Nernst equation.

This equation states that;

E = E°cell - 0.592/n log Q

Where

E = EMF under non standard conditions

E°cell= standard EMF of the cell

n = number of electrons transferred

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If the reaction quotient is greater than 1 then cell potential is less than the standard cell potential.

The cell that generates the lowest cell potential is the cell depicted in option C because Q has the greatest positive value(Q<1).

6 0
3 years ago
If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce
Natali5045456 [20]
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over
5 0
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The first method of determining the chemical composition of substances in space was to _____.
Art [367]

Answer:The first method to determine the chemical composition of a substance in space was using light. By determining red shift in the observed spectrum of light they could determine the elements they were observing

Explanation:

5 0
3 years ago
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