Answer:
The
of a substrate will be "10 μM".
Explanation:
The given values are:
![E_{t} = 20 \ nM](https://tex.z-dn.net/?f=E_%7Bt%7D%20%3D%2020%20%5C%20nM)
![[Substract] = 40 \ \mu M](https://tex.z-dn.net/?f=%5BSubstract%5D%20%3D%2040%20%5C%20%5Cmu%20M)
![K_{cat}=600 \ s^{-1}](https://tex.z-dn.net/?f=K_%7Bcat%7D%3D600%20%5C%20s%5E%7B-1%7D)
Reaction velocity, ![Vo=9.6 \ \mu M s^{-1}](https://tex.z-dn.net/?f=Vo%3D9.6%20%5C%20%5Cmu%20M%20s%5E%7B-1%7D)
As we know,
⇒ ![Vo=\frac{K_{cat}[E_{t}][S]}{K_{m}+[S]}](https://tex.z-dn.net/?f=Vo%3D%5Cfrac%7BK_%7Bcat%7D%5BE_%7Bt%7D%5D%5BS%5D%7D%7BK_%7Bm%7D%2B%5BS%5D%7D)
On putting the estimated values, we get
⇒ ![9.6=\frac{600\times 20\times 10^{-3}\times 40}{K_{m}+40}](https://tex.z-dn.net/?f=9.6%3D%5Cfrac%7B600%5Ctimes%2020%5Ctimes%2010%5E%7B-3%7D%5Ctimes%2040%7D%7BK_%7Bm%7D%2B40%7D)
⇒ ![K_{m}+40=\frac{600\times 20\times 10^{-3}\times 40}{9.6}](https://tex.z-dn.net/?f=K_%7Bm%7D%2B40%3D%5Cfrac%7B600%5Ctimes%2020%5Ctimes%2010%5E%7B-3%7D%5Ctimes%2040%7D%7B9.6%7D)
⇒ ![K_{m}+40=50](https://tex.z-dn.net/?f=K_%7Bm%7D%2B40%3D50)
On subtracting "40" from both sides, we get
⇒ ![K_{m}+40-40=50-40](https://tex.z-dn.net/?f=K_%7Bm%7D%2B40-40%3D50-40)
⇒ ![K_{m}=10 \ \mu M](https://tex.z-dn.net/?f=K_%7Bm%7D%3D10%20%5C%20%5Cmu%20M)
The number of atoms in one mole of any substance is measured by Avogadro's number. The value of Avogadro's number is 6.023 x 10 ^23. It is named after scientist Avogadro who proposed this number. 12 grams of carbon-12 represents 1 mole of carbon-12. For this reason, the number of atoms present in 1 mole of any substance is 6.023 x 10 ^23. Therefore, the number of atoms present in 1 mole carbon-12 is 6.023 x 10^23.
(Answer) This unit is the number of atoms in 12 grams of carbon-12 and known as Avogadro's number.
What? It would be nice if you show pic
Answer: Cycling of carbon in the
ocean is also expected As water moves through and across soils, it carries
valuable nutrients.