Answer: 1.00 M
Explanation:
Moles of Solute/Liters of Solution = molarity. Then you would do 0.500 Moles/ 0.500 L and you get 1.00 M.
Answer:
The pressure in the gas is 656mmHg
Explanation:
In calculating the pressure of the gas;
step 1: convert the height of the mercury arm to mmHg
9.60cm = 96.0 mmHg
step 2: convert 752 torr to mmHg
I torr is 1 mmHg
752 torr = 752mmHg
Step 3: since the level of mercury in the container is higher than the level of mercury exposed to the atmosphere, we substrate the values to obtain our pressure.
So, 752mmHg - 96mmHg = 656mmHg
The pressure in the gas container is therefore 656mmHg.
N. B : if the mercury arm is in lower position, you add.
Answer :
- Carbonyl group : It is a functional group composed of a carbon atom that double bonded to oxygen atom. It is represented as

Carboxylic group : It is the class of organic compound in which the carboxylic (-COOH) group is attached to a hydrocarbon is known as carboxylic.
The general formula of carboxylic is,
. According to the IUPAC naming, the carboxylic are named as alkanoic acids.
Aldehyde group : It is the class of organic compound in which the (-CHO) group is attached to a hydrocarbon is known as aldehyde.
The general representation of aldehyde is,
. According to the IUPAC naming, the aldehyde are named as alkanals.
Ketone group : It is the class of organic compound in which the (-CO) group is directly attached to the two alkyl group of carbon is known as ketone.
The general representation of ketone is,
. According to the IUPAC naming, the ketone are named as alkanone.
Ester group : It is the class of organic compound in which the (-COO) group is directly attached to the two alkyl group of carbon is known as ester.
The general representation of ester is,
. According to the IUPAC naming, the ester are named as alkyl alkanoate.
Answer:
0.025 L
Explanation:
The production of oxygen in the electrolysis of water is;
4OH^-(aq) -----> 2H2O(l) + O2(g) + 4e
Since 1 F = 96500C
molar volume of a gas = 22.4 L
From the reaction equation;
4 * 96500 C yields 22.4 L of oxygen
(3 * 60 * 60 * 0.0400) C yields (3 * 60 * 60 * 0.0400) * 22.4/4 * 96500
= 9676.8/386000
= 0.025 L
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