When 1.00 L of a 0.500 M LiBr solution is tripled by dilution with water . the number of moles of lithium in new solution is 0.5 moles.
given that :
volume = 1.00 L
molarity = 0.500 M
The solution is tripled by dilution but there will be no effect in number of mole by the dilution.
the number of moles = molarity × volume in L
the number of moles = 1 × 0.500
the number of moles = 0.5 mol
Thus, When 1.00 L of a 0.500 M LiBr solution is tripled by dilution with water . the number of moles of lithium in new solution is 0.5 moles.
To learn more about number of moles here
brainly.com/question/14919968
#SPJ4
Hydrogen on sharing its one electron with chlorine results in formation of hydrogen chloride molecule and chlorine and hydrogen complete its octet by sharing one electron of each and thus forming a single covalent bond by sharing of two electrons.
Answer:
unsaturated
Explanation:
All solutions have a definite capacity of dissolving solute in it.
Unsaturated solutions are the solutions which contain less amount of solute than the maximum capacity of dissolving the solute. If more amount of solute is added in such a way a point is reached where addition of more solute cannot be dissolved. The solution is known as saturated solution.
Amount dissolved > Maximum solubility limit, the solution is saturated.
Amount dissolved < Maximum solubility limit, the solution is unsaturated.
If the amount of the salt exceeds the solubility limit, then the solution is saturated solution. If it is less than the limit given, then it is unsaturated solution.
The solubility = 0.667 grams per liter
Amount dissolved = 0.502 grams per liter
Since,
Amount dissolved < Maximum solubility limit, the solution is unsaturated.
First, find the number of moles of glucose in 30.5 g.
You need the molar mass.
Molar mass of C6H12O6 = 6 * 12.01 g/mol + 12 * 1.01 g/mol + 6*16g/mol = 180.2 g/mol
number of moles = mass in grams / molar mass = 30.5 g / 180.2 g/mol = 0.169 mol
Second, use molecular formula
1 mol of C6H12O6 contains 6 moles of O.
Then, 0.169 moles of C6H12O6 contains 6 *0.169 = 1.014 moles of O.
Third, multiply by Avogagro's number:
1.014 moles * 6.022 * 10^23 atoms / mole = 6.106 * 10^ 23 atoms.
Answer: 6.106 * 10 ^23 atoms of oxygen.
