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marishachu [46]
3 years ago
9

Iron is much denser than a feather. yet, a particular sample of feathers weighs more than a sample of iron. explain how this is

possible.
Chemistry
2 answers:
Anit [1.1K]3 years ago
8 0
Answer is: density doesn't affect on weigh.
Density <span>of a substance is its </span>mass<span> per unit </span>volume, <span>density is defined as mass divided by volume (d = m/V).
</span>Weight is force<span> on the object due to </span>gravity. Weight is <span>product of the </span>mass<span> of substance and the magnitude of the local </span>gravitational acceleration (<span>W = <span>mg). Feather can have larger mass and also weight.</span></span>
Naddik [55]3 years ago
4 0
<span>How iron can be more dense as a feather yet more feathers can weigh more is because density and weight are two completely different things. No matter how many feathers there are it's density never changes, it's weight is able to change but not density. Therefore the density of iron is higher no matter what but may weigh less than a group of feathers.</span>
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What happens when energy is added to each state?
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Answer:

One change of state happens when you add energy to the substance. This change of state is called melting. By adding energy to the molecules in a solid the molecules begin to move quicker and can break away from the other molecules. ... The temperature at which a substance goes from a solid to a liquid is it melting point.

5 0
3 years ago
0.820 L has a mass of 2.56kg what is the density of this liquid in kg/L
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Density ρ=\frac{m}{v}

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3 years ago
Calculate the approximate volume of a 0.6000mol sample of gas at 288.15K and a pressure of 1.10atm.
11111nata11111 [884]

Answer:

The volume of the sample of the gas is found to be 12.90 L.

Explanation:

Given pressure of the gas = P = 1.10 atm

Number of moles of gas = n = 0.6000 mole

Temperature = T = 288.15 K

Assuming the volume of the gas to be V liters

The ideal gas equation is shown below

\textrm{PV} =\textrm{nRT} \\1.10 \textrm{ atm}\times V \textrm{ L} = 0.6000 \textrm{ mole}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 288.5\textrm{K} \\\textrm{V} = 12.90 \textrm{ L}

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6 0
4 years ago
When a substance changes from one phase to another, which of the following occurs? A. The substance loses or gains heat. B. The
a_sh-v [17]

A the substance loses or gains heat

6 0
3 years ago
Read 2 more answers
2. The change in internal energy for the expansion of a gas sample is -4750 J. How much work is done if the gas sample loses 112
Radda [10]

Answer:

The work done by the gas expansion is 5875 J,

Since the work done is positive, the work is done by the gas on the surroundings.

Explanation:

Given;

change in internal energy, ΔU = -4750 J

heat transferred to the system, Q = 1125 J

The change in internal energy is given by;

ΔU = Q - W

Where;

W is the work done by the system

The work done by the system is calculated as;

W = Q - ΔU

W =  1125 - (-4750)

W = 1125 + 4750

W = 5875 J

Since the work done is positive, the work is done by the gas on the surroundings (energy flows from the gas to the surroundings).

Therefore, the work done by the gas expansion is 5875 J

7 0
3 years ago
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