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ehidna [41]
2 years ago
13

A student used 10 mL water instead of 30mL for the extraction of the NaCl from the mixture. How would this affect the calculated

percentage of NaCl in the sample?
Chemistry
1 answer:
Usimov [2.4K]2 years ago
7 0
The amount of Nacl would be 3 times more
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Which of the following is NOT a type of mucle tissue?
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Striped should be the answer

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10. On the basis of the general solubility rules given
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I think it’s c but I could be wrong
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Calculate the percent of lead in Pb (Co3)2
velikii [3]
We will take that molar mass of Pb(CO3)2 represents the total mass of all particles in this compound, ie it has value 100%.

M(Pb(CO3)2) = Ar(Pb) + 2xAr(C) + 6xAr(O) = 207.2 + 2x12 + 6x16= 327.2 g/mol

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From the date above we can set the following ratio:

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7 0
3 years ago
During a chemical change items are lost or gained to make new substance true or false​
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3 years ago
What mass of KNO3 would be needed to produce 18.4 liters of oxygen gas, measured at 1.50 x 10^3 kPa and 15 degrees Celsius?
Brut [27]

Answer:-

2328.454 grams

Explanation:-

Volume V = 18.4 litres

Temperature T = 15 C + 273 = 288 K

Pressure P = 1.5 x 10^ 3 KPa

We know universal Gas constant R = 8.314 L KPa K-1 mol-1

Using the relation PV = nRT

Number of moles of oxygen gas n = PV / RT

Plugging in the values

n = (1.5 x 10^3 KPa ) x ( 18.4 litres ) / ( 8.314 L KPa K-1 mol-1 x 288 K)

n = 11.527 mol

Now the balanced chemical equation for this reaction is

2KNO3 --> 2KNO2 + O2

From the equation we can see that

1 mol of O2 is produced from 2 mol of KNO3.

∴ 11.527 mol of O2 is produced from 2 x 11.527 mol of KNO3.

= 23.054 mol of KNO3

Molar mass of KNO3 = 39 x 1 + 14 x 1 + 16 x 3 = 101 grams / mol

Mass of KNO3 = 23.054 mol x 101 gram / mol

= 2328.454 grams

7 0
3 years ago
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