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SpyIntel [72]
3 years ago
13

Suppose wave pulses in an aquarium are produced by a mechanical motor that moves a bob up and down at the surface. The setup use

s a 10-W motor and has a period of 1.9 s between bobs. How much kinetic energy is in each pulse.
Physics
1 answer:
-Dominant- [34]3 years ago
3 0

Answer:

kinetic energy in each pulse = 9.5J

Explanation:

  • The concept used here is that of work, energy and power.

  • Power P = Work /Time

  • Work = energy in this case

  • E = Power x time = Pt

  • but Power = 10W and t = 1.9s

  • Energy E = 10W x 1.9s = 19J

Conventionally, overall energy = kinetic + potential

Hence kinetic energy in each pulse = half of the total energy = 0.5 x 19

energy = 9.5J

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A book prone to air resistance is released from rest 300 m
yaroslaw [1]

Answer:

Approximately 73\%.

(Assuming that g = \rm 9.81\; m \cdot s^{-2}.)

Explanation:

The mechanical energy of an object is the sum of its potential energy and its kinetic energy. It will be shown that the exact mass of this object doesn't matter. For ease of calculation, let m(\text{book}) represent the mass of the book.

The initial potential energy of the book is  

\begin{aligned}U(300\; \text{m}) &= m(\text{book}) \cdot g \cdot \Delta h + U(0\; \text{m}) \cr &=(9.81 \times 300) \cdot m(\text{book})\cr &= \left(2.943\times 10^3\right) \cdot m(\text{book})\end{aligned}.

The book was initially at rest when it was released. Hence, its initial kinetic energy would be zero. Hence, the initial mechanical energy of the book-Earth system would be (2.943\times 10^3) \cdot m(\text{book}).

When the book was about to hit the ground, its speed is \rm 40\; m \cdot s^{-1}. Its kinetic energy would be:

\begin{aligned} \text{KE} &= \frac{1}{2} \, m(\text{book}) \cdot v^{2} \cr &= \left(\frac{1}{2} \times 40^2\right)\cdot m(\text{book}) \cr &= \left(8.00\times 10^2\right)\cdot m(\text{book})\end{aligned}.

The question implies that the potential energy of the book near the ground is zero. Hence, the mechanical energy of the system would be \left(8.00\times 10^2\right)\cdot m(\text{book}) when the book was about to hit the ground.

The amount of mechanical energy lost in this process would be equal to:

\begin{aligned}&\left(2.943\times 10^3\right) \cdot m(\text{book}) - \left(8.00\times 10^2\right)\cdot m(\text{book}) \cr &=\left(2.143\times 10^3\right)\cdot m(\text{book})\end{aligned}.

Divide that with the initial mechanical energy of the system to find the percentage change. Note how the mass of the book, m(\text{book}), was eliminated in this process.

\begin{aligned}&\frac{\left(2.143\times 10^3\right)\cdot m(\text{book})}{\left(2.943\times 10^3\right) \cdot m(\text{book})}\times 100\% \cr &= \frac{2.143\times 10^3}{2.943\times 10^3}\times 100\% \cr & \approx 73\%\end{aligned}.

5 0
3 years ago
Earth rotates on its axis once every 24 hours, so that objects on its surface execute uniform circular motion about the axis wit
fgiga [73]

Answer:

The effect of this rotation on the person on the surface is the sky is moving, like an apparent diurnal motion.

Explanation:

<em>For an observer at a fixed position on Earth, the rotation of earth makes it appear as if the sky is revolving around the earth. In other words, if a person is standing for long enough in a field at night, it looks like the sky is moving, not the person. This motion is called "apparent diurnal motion." </em>

<em>Diurnal means having to do with a day, in a sense of a 24- hour period.</em>

5 0
3 years ago
Arm abcd is pinned at b and undergoes reciprocating motion such that θ=(0.3 sin 4t) rad, where t is measured in seconds and the
storchak [24]
<span>θ=0.3sin(4t)
w=0.3cost(4t)(4)=1.2cost(4t)
a=-4.8sin(4t)

cos4t max will always be 1 (refer to cos graph), for same reason, sin4t will always be 0

therefore, wmax=1.2rad/s
 
vAmax=r*w=250*1.2=300mm/s
(may be different if your picture/radius is from a different picture)

adt=a*r=200*-4.8sin(4t)=0 (sin(4t)=0)

adn=r*w^2=200*1.2^2=288

ad= square root of adt^2+adn^2 = 288mm/s^2</span>
8 0
3 years ago
Which of the following is not a part of a wave?
Alisiya [41]
B is the correct answer
y=Asin(wt-kx)
A=amplitude
f=frequency
x=wavelength
since refraction is not on the wave formula,then option B is the correct answer
5 0
3 years ago
Read 2 more answers
A train travels 94 kilometers in 5 hours, and then 84 kilometers in 3 hours. What is its average speed?
diamong [38]
Average speed equal to = ,total distance traveled/total time taken
so it would be = 94+84/8
= 22.25 kmph
3 0
3 years ago
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