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SpyIntel [72]
3 years ago
13

Suppose wave pulses in an aquarium are produced by a mechanical motor that moves a bob up and down at the surface. The setup use

s a 10-W motor and has a period of 1.9 s between bobs. How much kinetic energy is in each pulse.
Physics
1 answer:
-Dominant- [34]3 years ago
3 0

Answer:

kinetic energy in each pulse = 9.5J

Explanation:

  • The concept used here is that of work, energy and power.

  • Power P = Work /Time

  • Work = energy in this case

  • E = Power x time = Pt

  • but Power = 10W and t = 1.9s

  • Energy E = 10W x 1.9s = 19J

Conventionally, overall energy = kinetic + potential

Hence kinetic energy in each pulse = half of the total energy = 0.5 x 19

energy = 9.5J

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In the car experiment you completed what part of the scientific method would the following statement be classified as?
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answer:

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explanation:

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Is the following true or false? Continental glaciers fill depressions in the surface with water, where they create cirques.
Lorico [155]
False is the answer to your question
6 0
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A baseball has a mass of 0.145 kg. A professional pitcher throws a baseball 67 mi/h, which is 30.0 m/s. What is the magnitude of
Kamila [148]

The concept of momentum tells us that it is equivalent to the product between the mass and the velocity of the object, that is to say that in general it can be written as

p = mv

Where,

m = mass

v = Velocity

Our values are given as,

m = 0.145kg

v = 67mi/h = 30m/s

Replacing we have that,

p = (0.145)(30)

p = 12.45 kg\cdot m/s

Therefore the magniude of the momentum of the pitched baseball is 12.45 kg\cdot m/s

6 0
3 years ago
Read 2 more answers
A merchant in Katmandu sells you a solid gold 1.00-kg statue for a very reasonable price. When you get home, you wonder whether
White raven [17]

Answer:

a) 51.8 cm³

b) kg/m³ is a dimension of density (mass/volume). The regular unitys for volume are m³, cm³, L, gallons.

Explanation:

a) The density of pure gold is 19.3 g/cm³. When put in water, the piece of gold will occupy a volume, so that the volume of water will be displaced. To know the volume, we must divide the mass for the density (mass must be in grams because of the units of the density)

V = 1000/19.3

V = 51.8 cm³

7 0
3 years ago
At what distance from Earth does the force of gravity exerted by Earth on the coasting spacecraft cancel the force of gravity ex
telo118 [61]

Answer:

346 * 10⁶ m

Explanation:

The force of gravity of the earth that will cancel the the force of gravity exerted by the moon will be equal to each other

Let F_{e} be the force of gravity exerted by the earth

and let F_{m} be the force of gravity exerted by the moon

According to Newton's law of universal gravitation, the force of attraction between two different masses, m₁ and m₂ separated by a distance, d,  is given by:

F = \frac{Gm_{1} m_{2} }{d^{2} }

Mass of the earth, m_{e} = 5.97 * 10^{24} kg

Mass of the moon, m_{m} = 7.348 * 10^{22} kg

Mass of the satellite, m_{s} = ?

F_{e}  = \frac{G*5.97 * 10^{24} M }{d^{2} }...............................(1)

The earth and the moon are separated by a distance, 3.844 * 10⁸ m

F_{m}  = \frac{G*7.348 * 10^{22} M }{(3.844 * 10^{8} - d) ^{2} }............................(2)

Equating equations (1) and (2)

\frac{5.97 * 10^{24} }{d^{2} } = \frac{7.348 * 10^{24} }{(3.844* 10^{8} -d)^{2} }

(5.97 * 10^{24})(14.78 * 10^{16}  -7.688*10^{8}d + d^{2}) = 7.348 * 10^{24} d^{2} \\88.24*10^{40} - 45.9 * 10^{32}d +  5.97 * 10^{24}d^{2} =  7.348 * 10^{24} d^{2}\\ 1.378 * 10^{24}d^{2} + 45.9 * 10^{32}d + 88.24*10^{40} = 0\\

Factorising out 10^{24}

1.378d^{2} + 45.9 * 10^{8}d + 88.24*10^{16} = 0

Solving for d in the quadratic equation  above:

d = 346 * 10⁶ m

4 0
3 years ago
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