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zvonat [6]
3 years ago
13

In some amazing situations, people have survived falling large distances when the surface they land on is soft enough. During a

traverse of Eiger's infamous Nordvand, mountaineer Carlos Ragone's rock anchor gave way and he plummeted 515 feet to land in snow. Amazingly, he suffered only a few bruises and a wrenched shoulder. Assuming that his impact left a hole in the snow 3.5 ft deep, estimate his average acceleration as he slowed to a stop (that is while he was impacting the snow). Pick a coordinate system where down is positive.
Physics
1 answer:
kicyunya [14]3 years ago
5 0

Have you seen my dad?

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How can "Ali" distinguish the interference patterns produced by diffraction gratings from the interference patterns produced by
I am Lyosha [343]

Answer:

The interference pattern from a diffraction grating will have a wide, central bright band with alternate dark and bright bands on both sides, and the interference pattern will have an equally spaced dark and bright band.

Explanation:

In diffraction pattern we know that the distance between two consecutive minimum position is maximum

So here position of minimum is given as

asin\theta = N\lambda

now we have central maximum is of maximum width while all other have width of decreasing order.

While when we use Young's double slit pattern then we can say that position of all maximum and minimum intensity on the screen will be at same distance.

so here we have

y = \frac{N\lambda L}{d}

so all the maximum and minimum intensity will have equal width.

3 0
3 years ago
A household has a three-month electricity bill of $425. If the average unit cost of electricity is 8.5c, find:
Hunter-Best [27]

OK.  We can do this.

3 months = 90 days

The unit cost is  ($0.085) per kilowatt-hour

Here we go:

($ 425/90da) · (1da/24hr) · (1 da/86,400sec) · (1 kW-hr/$ 0.085) =

(425 · 1 · 1 · 1) / (90 · 24 · 86,400 · 0.085) · ($-da-da-kW-hr / da-hr-sec-$) =

2.679 x 10⁻⁵ day-kW/sec

This is not too useful yet.  It needs some more unit conversion.

I think all it needs is another  (1 day = 86,400 sec) .

(2.679 x 10⁻⁵ day-kW/sec) · (86,400 sec / da) =  

(2.679 x 10⁻⁵ · 86,400) · (da-kW-sec / sec-da) =

<em>2.315 kW</em>

If I have not gang aglay somewhere in all of that, then this is the answer to the question:  <em>2.315 kW .</em>

I know that you probably didn't follow everything that I did, and if you did, you don't have a lot of confidence in this answer.  I have to admit that I have serious doubts too.  So I have to check the answer somehow.

What would it cost if the household was using power steadily at the rate of 2.315 kilowatts, and the family went away for three months and just left everything cooking like that ?

2.315 kilowatts ===> <u>2.315 kilowatt-hours</u> every hour

(2.315 kW hours per hr) x (24 hrs per day) = <u>55.56 kWh per day</u>

(55.56 kWh per day) x (90 days) = <u>5,000.4 kWh</u>

(5,000.4 kWh) x (8.5¢ for each kWh) = <u>42,503.4¢ on the bill</u>

42,503.4¢  =  $425.034  That's good enough for me ! !  I rest my case.

5 0
3 years ago
Red and orange stars are found evenly spread throughout the galactic disk, but blue stars are typically found ________.
Anni [7]
I think the answer is
6 0
3 years ago
A skier starts at the top of a very large, frictionless snowball, with a very small initial speed, and skis straight down the si
dangina [55]

Answer:

The answer to the question is

At the instant she loses contact with the snowball, the angle (alpha) a radial line from the center of the snowball to the skier make with the vertical is 48.2 °

Explanation:

At the point where the skier loses contact with the snpwball we have the centripetal force given by

m·g·cos θ - N = m\frac{v^2}{R}

Where  N = 0 at the point the skier leaves the snowball

That is

 m·g·cos θ  = m\frac{v^2}{R}

The height from which the skier drops from the snowball is given by

h = r - r·cosθ

Therefore the potential energy of the skier just before leaveing the snowball is

m·g·h = m·g·r·(1-cosθ)

From conservation of energy, the total energy of the skier is constant which means that is the potential energy is transformed to kinetic energy of the form

PE = KE That is  

\frac{1}{2} mv^2 = m·g·r·(1-cosθ) or

m\frac{v^2}{R} = 2·m·g·(1-cosθ) Howerver since   m·g·cos θ  = m\frac{v^2}{R} then we have

m·g·cos θ  = 2·m·g·(1-cosθ)  which gives

cosθ = 2·(1-cosθ) or 3·cosθ = 2

or cosθ =  \frac{2}{3} and θ = cos^{-1}\frac{2}{3} = 48.1896851 °

≈48.2 °

7 0
4 years ago
The electric force between two charged particles is 0.18 newtons. If the distance between them is increased by a factor of 3.0,
Brut [27]
.18 newtons= 3.0 i say this because i need to be the brainlyest
5 0
3 years ago
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