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Ronch [10]
4 years ago
11

What is the scale factor?

Chemistry
1 answer:
professor190 [17]4 years ago
4 0

Answer:

Scale Factor: 1 : 2

X = 11

Explanation:

3 / 3 = 1

6 / 3 = 2

The scale factor should be 1:2

So 'X' should be 11 since 5.5 * 2 = 11

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3 years ago
Once formed, how many valence electrons does an anion hold?
Elena-2011 [213]

Answer:

Anions. Some atoms have nearly eight electrons in their valence shell and can gain additional valence electrons until they have an octet. When these atoms gain electrons, they acquire a negative charge because they now possess more electrons than protons. Negatively charged ions are called anions.

7 0
3 years ago
328. mL of 0.00345 M NaI (aq) is combined with 703. mL of 0.00802 M Pb(NO3)2 (aq). Determine if a precipitate will form given th
Vsevolod [243]

Answer:

The solution will not form a precipitate.

Explanation:

The Ksp of PbI₂ is:

PbI₂(s) ⇄ 2I⁻(aq) + Pb²⁺(aq)

Ksp = 1.40x10⁻⁸ = [I⁻]²[Pb²⁺] <em>Concentrations in equilibrium</em>

When 328mL of 0.00345M NaI(aq) is combined with 703mL of 0.00802M Pb(NO₃)₂. Molar concentration of I⁻ and Pb²⁺ are:

[I⁻] = 0.00345M × (328mL / (328mL+703mL) =<em> 1.098x10⁻³M</em>

[Pb²⁺] = 0.00802M × (703mL / (328mL+703mL) =<em> 5.469x10⁻³M</em>

<em />

Q = [I⁻]²[Pb²⁺] <em>Concentrations not necessary in equilibrium</em>

If Q = Ksp, the solution is saturated, Q > Ksp, the solution will form a precipitate, if Q < Ksp, the solution is not saturated.

Replacing:

Q = [1.098x10⁻³M]²[5.469x10⁻³M] = 6.59x10⁻⁹

As Q < Ksp, the solution is not saturated and <em>will not form a precipitate</em>.

6 0
3 years ago
TRY H Vele
Strike441 [17]
<h3>Answer:</h3>

Al- [Ne] 3s²3p¹

As- [Ar] 4s²3d¹⁰ 4p³

Explanation:

  • Electron configuration of an element shows the arrangement of electrons in the energy levels or orbitals in the atom.
  • Noble-gas configuration involves use of noble gases to write the configuration of other elements.
  • This is done by identifying the atomic number of the element and then identifying the noble gas that comes before that particular element on the periodic table.
  • For example:
  1. Aluminium: The atomic number of Al is 13. The noble gas before Aluminium is Neon which has 10 electrons. Therefore the remaining 3 electrons fills up the 3s and 3p sub orbitals.
  • Thus, the noble-gas configuration of Al is [Ne] 3s²3p¹

     2.  Arsenic, Atomic number is 33

  • Noble gas before Arsenic is Ar,. Argon has 17 electrons, then the remaining electrons fills up the 4s, 3d and 4p sub-orbitals.
  • Thus, the noble-gas configuration of As is [Ar] 4s²3d¹⁰ 4p³
6 0
3 years ago
Which statement best describes the oxidation numbers of the atoms found in magnesium chloride? A. Magnesium has a 2- oxidation n
In-s [12.5K]
B. is the correct answer of your question
6 0
4 years ago
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